SQL2等效于此XPath查询

Question

是否有SQL2查询与以下XPath查询相同：

/jcr:root/content/ancestor//parent/jcr:content

它应该返回以下节点，例如：

/content/ancestor/a/b/c/parent/jcr:content
/content/ancestor/a/parent/jcr:content
/content/ancestor/parent/jcr:content

但不是以下节点：

/content/xxx/a/b/c/parent/jcr:content
/content/xxx/a/parent/jcr:content
/content/xxx/parent/jcr:content

Answer 1

以下应该工作：

SELECT * FROM [nt:base] AS s 
  INNER JOIN [nt:base] AS parent
    ON ISCHILDNODE(s, parent)
WHERE
  ISDESCENDANTNODE(s, [/content/ancestor]) AND
  NAME(parent) = 'parent' AND
  NAME(s) = 'jcr:content'

如果s的类型为cq:PageContent且parent的类型为cq:Page，您可以使用此信息来加快查询速度：

SELECT * FROM [cq:PageContent] AS s 
  INNER JOIN [cq:Page] AS parent
    ON ISCHILDNODE(s, parent)
WHERE
  ISDESCENDANTNODE(s, [/content/ancestor]) AND
  NAME(parent) = 'parent' AND
  NAME(s) = 'jcr:content'

Answer 2

您可以使用crxde 中的“查询工具”轻松地将xpath转换为sql2，反之亦然