Question

为什么此查询没有考虑“c.max_no_people＆lt; = $ max_guests”的Where子句？

SELECT DISTINCT a.id, b.post_id, c.max_no_people
FROM wp_dopbsp_reservations a
    INNER JOIN wp_dopbsp_calendars b
    ON ( b.id = a.calendar_id)
    INNER JOIN wp_dopbsp_settings c
    ON ( b.id = c.calendar_id )
WHERE (a.check_out >= \"$check_in\"
            AND a.check_in < \"$check_out\"
            OR a.check_out <= \"$check_in\"
            AND a.check_in > \"$check_out\")
    AND (c.max_no_people <= $max_guests)
    AND (a.status = 'approved')

提前致谢。

Answer 1

试试这个：

SELECT DISTINCT a.id, b.post_id, c.max_no_people
FROM wp_dopbsp_reservations a
INNER JOIN wp_dopbsp_calendars b
ON ( b.id = a.calendar_id)
INNER JOIN wp_dopbsp_settings c
ON ( b.id = c.calendar_id )
WHERE a.check_out >= \"$check_in\"
        AND (a.check_in < \"$check_out\"
        OR a.check_out <= \"$check_in\")
        AND a.check_in > \"$check_out\"
AND (c.max_no_people <= $max_guests)
AND (a.status = 'approved')

这是因为你在不使用括号的情况下给出了OR语句。所以它只考虑OR语句。

Answer 2

嗯，我认为问题出在这里

(a.check_out >= \"$check_in\"
 AND a.check_in < \"$check_out\"
 OR a.check_out <= \"$check_in\"
 AND a.check_in > \"$check_out\")

不应该：

(
 (a.check_out >= \"$check_in\"
 AND a.check_in < \"$check_out\") OR
( a.check_out <= \"$check_in\"
 AND a.check_in > \"$check_out\")
)

同样逃避 $ max_guests ，如（int）$ max_guests

MySQL双连接多个Where子句

2 个答案: