Question

我有两个模型用户和员工需要互相交流。这是一个基于示例应用程序（controller）的控制器。我需要它适用于两个模型，但为def等邮箱等添加if / else语句以确定员工或用户是否登录显示“堆栈级别太深”错误。我是rails的新手，无法理解多次谷歌搜索/ SO后我的错误。消息传递应该在这两个模型之间，并且发起者应该是用户。（更新：我找到了一篇SO帖子Mailboxer Gem--Restrict messaging）万分感谢！

class ConversationsController < ApplicationController
  before_filter :authenticate_employee! or authenticate_user!
  helper_method :mailbox, :conversation

  def create
    recipient_emails = conversation_params(:recipients).split(',')
    recipients = User.where(email: recipient_emails).all
if(user_signed_in?)
    conversation = current_user.send_message(recipients, *conversation_params(:body, :subject)).conversation
else
  conversation = current_employee.send_message(recipients, *conversation_params(:body, :subject)).conversation
end
    redirect_to conversation_path(conversation)

end

  def reply
    current_user.reply_to_conversation(conversation, *message_params(:body, :subject))
    redirect_to conversation_path(conversation)
  end

  def trash
    conversation.move_to_trash(current_user)
    redirect_to :conversations
  end

  def untrash
    conversation.untrash(current_user)
    redirect_to :conversations
  end

  private

  def mailbox
    if(user_signed_in?)
    @mailbox ||= current_user.mailbox
else
    @mailbox ||= current_employee.mailbox
end
    redirect_to conversation_path(conversation)  
end


  def conversation
    @conversation ||= mailbox.conversations.find(params[:id])
  end

  def conversation_params(*keys)
    fetch_params(:conversation, *keys)
  end

  def message_params(*keys)
    fetch_params(:message, *keys)
  end

  def fetch_params(key, *subkeys)
    params[key].instance_eval do
      case subkeys.size
      when 0 then self
      when 1 then self[subkeys.first]
      else subkeys.map{|k| self[k] }
      end
    end
  end
end`

Answer 1

由于无限循环/递归/重定向，通常会出现“堆栈级太深”错误。看看上面的代码，我没有看到任何明显的罪魁祸首，但是使用pry进行调试可能会帮助你追踪它。

Mailboxer Gem使用多个模型

1 个答案: