我找到了一个教程,看起来它会像我一直试图做的那样没有成功。我根据我的细节调整了它并试了一下。它不起作用。当您输入搜索并点击提交时,它所做的就是回到开头。我无法看到代码有什么问题所以经过几个小时的尝试后,就在这里。你能看出出了什么问题吗?
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="content-type" content="text/html;charset=utf-8" />
<title>test</title>
</head>
<body>
<?
if ($searching =="yes")
{
echo "<h2>Search</h2><p>";
if ($find == "")
{
echo "<p>You forgot to enter a search term";
exit;
}
mysql_connect('localhost', 'user', 'password') or die(mysql_error());
mysql_select_db("database") or die(mysql_error());
$find = strtoupper($find);
$find = strip_tags($find);
$find = trim ($find);
$data = mysql_query("SELECT * FROM engravers WHERE upper($field) LIKE'%$find%'");
while($result = mysql_fetch_array( $data ))
{
echo $result['Country'];
echo "<br>";
echo $result['Year'];
echo "<br>";
echo $result['Engraver1Surname'];
echo "<br>";
echo $result['Designer1Surname'];
echo "<br>";
echo $result['Printer'];
echo "<br>";
echo "<br>";
}
$anymatches=mysql_num_rows($data);
if ($anymatches == 0)
{
echo "Sorry, but we can not find an entry to match your query<br><br>";
}
echo "<b>Searched For:</b> " .$find;
}
?>
<h2>Search</h2>
<form name="search" method="post" action="<?=$PHP_SELF?>">
Search for: <input type="text" name="find" /> in
<Select NAME="field">
<Option VALUE="Country">Country</option>
<Option VALUE="Year">Year</option>
<Option VALUE="Engraver1Surname">Engraver</option>
<Option VALUE="Designer1Surname ">Designer</option>
<Option VALUE="Printer">Printer</option>
</Select>
<input type="hidden" name="searching" value="yes" />
<input type="submit" name="search" value="Search" />
</form>
</body>
</html>
答案 0 :(得分:1)
正如我的评论中所提到的,在POST
之后,您需要从$_POST
数组中获取变量。类似的东西:
if ($_POST['searching'] == "yes") {
$find = $_POST['find'];
$field = $_POST['field'];
// etc...
答案 1 :(得分:0)
这看起来像是register_globals
开启的非常旧的PHP代码。它不起作用like that anymore。
使用超全球$_POST
来获取变量,例如:
if ($_POST['searching'] =="yes") {
...
}
另外,请阅读SQL注入和how to avoid it。
答案 2 :(得分:0)
您需要在begin:
上设置变量//set default values
$find="";
$searching="";
$field="";
If(isset($_POST['searching']) && $_POST['searching']="yes"){
$find= mysql_real_escape_string($_POST['find']);
$searching=mysql_real_escape_string($_POST['searching']);
$field=mysql_real_escape_string($_POST['field']);
...