Question

我想用rspec测试API控制器。所以这是一段简单的代码：

require 'rails_helper'  
describe "GET /api/config" do

  it 'routes GET to /api/config to Api::V1::ConfigsController#show' do
    get '/api/config.json'
    expect(response).to be_success
  end

end

但我有一个错误：

1) Configs API GET /api/config routes GET to /api/config to Api::V1::ConfigsController#show
     Failure/Error: expect(response).to be_success
     NameError:
       undefined local variable or method `response' for #<RSpec::ExampleGroups::ConfigsAPI::GETApiConfig:0x007f84d93fbb90>
     # ./spec/routing/api/v1/devise/configs_routing_spec.rb:13:in `block (3 levels) in <top (required)>'

Answer 1

在RSpec 3你会做：

get '/api/config.json'
expect(response.status).to be(200)

Answer 2

您的控制器规格是否在specs / controller目录中？如果没有，那么Rspec需要您通过使用元数据:type => :controller标记描述来明确声明它们是控制器规范。这是因为仅当您的规范设置为控制器规范时，response变量才可用即

require 'rails_helper'  
describe "GET /api/config", type: :controller do

  it 'routes GET to /api/config to Api::V1::ConfigsController#show' do
    get '/api/config.json'
    expect(response).to be_success
  end

end

另请查看here

Answer 3

您可以尝试使用此语法

describe "GET /api/config", type: :controller do

  it 'routes GET to /api/config to Api::V1::ConfigsController#show' do
    get '/api/config.json'
    expect(last_response.status).to be(200)
  end

end

使用expect(last_response.status).to be(200)而非响应

对我有用！

供参考：我正在使用rails 5

Rspec 3.未定义的局部变量或方法`response＆＃39; for＃<rspec :: examplegroups :: configsapi :: getapiconfig：0x007f84d93fbb90> </rspec :: examplegroups :: configsapi :: getapiconfig：0x007f84d93fbb90>

3 个答案: