Question

我使用AFNetwoking v 2.2.4作为iOS上的网络库。它将非http 2xx（http 200为成功）响应视为错误，并抛出错误块，如下所示：

NSError *error= nil;
NSData * jsonData = [NSJSONSerialization dataWithJSONObject:user options:NSJSONWritingPrettyPrinted error:&error];
NSString *connectionString = [NSString stringWithFormat:@"%@%@",SERVER_URL, RESOURCE_URL_USER_SIGNUP];
NSURL *url = [NSURL URLWithString:connectionString];
NSMutableURLRequest *urlRequest = [NSMutableURLRequest requestWithURL:url];

[urlRequest setValue:@"application/json" forHTTPHeaderField:@"Accept"];
[urlRequest setValue:@"application/json" forHTTPHeaderField:@"Content-Type"];
[urlRequest setHTTPMethod:@"POST"];
[urlRequest setHTTPBody:jsonData];

AFHTTPRequestOperation *operation = [[AFHTTPRequestOperation alloc] initWithRequest:urlRequest];
operation.responseSerializer = [AFJSONResponseSerializer serializer];

[operation setCompletionBlockWithSuccess:^(AFHTTPRequestOperation *operation, id responseObject) {

    NSLog(@"response object: %@", (NSDictionary *)responseObject);

    [delegate userSignUpCompletedWithResponse:responseObject];

} failure:^(AFHTTPRequestOperation *operation, NSError *error) {
    NSLog(@"Error: %@", error);
    [delegate userSignUpFailedWithError:error];
    NSString *errorBodyMessage = [[error userInfo] objectForKey:@"NSLocalizedRecoverySuggestion"];
    NSLog(@"error message: %@", errorBodyMessage);

}];

[operation start];

这里，当http响应为200时，一切都按预期工作。我在服务器端有一个REST API，用ROR编写。对于用户注册，如果所有字段都有有效值，则它会发送200状态，但如果数据无效，例如已经采取电子邮件;在这种情况下，服务器发送422状态，并在JSON中显示错误消息。我需要跟踪错误消息并将其显示给移动用户，但我无法在错误块中获取消息对象。我记录了整个错误，但没有找到从服务器返回的对象。如果使用AFNetworking存在非2xx http响应，如何获取JSON对象？

Answer 1

访问传递给失败块的responseObject的{{1}}属性。

operation

如何在AFNetworking的http 422响应中获取返回的对象？

1 个答案: