在此代码中,hitboxes没有感知任何东西。该 如果用于检查2个命中框是否相交的语句是否在圆和矩形触摸时不进行操作。我如何让这个工作?
import java.awt.Graphics;
import java.awt.Rectangle;
import java.awt.event.KeyEvent;
import java.awt.event.KeyListener;
import java.awt.geom.Ellipse2D;
import java.awt.geom.Rectangle2D;
import java.util.Random;
import javax.swing.JFrame;
public class RunPaintGUI extends JFrame implements KeyListener {
int run = 10;
int x = 30;
int y = 30;
int score = 0;
Random randomgenerator = new Random();
int a = randomgenerator.nextInt(1220);
int b = randomgenerator.nextInt(700);
public static void main(String[] args) {
RunPaintGUI RunPaintGUI = new RunPaintGUI();
}
public RunPaintGUI() {
this.setSize(1275, 775);
this.setResizable(false);
this.setTitle("game");
this.setVisible(true);
this.addKeyListener(this);
}
public void paint(Graphics g) {
super.paint(g);
g.fill3DRect(x, y, 60, 60, true);
g.fillOval(a, b, 50, 50);
g.drawString("score: " + score, 600, 50);
}
Rectangle2D hitbox = new Rectangle(x, y, 60, 60);
Ellipse2D.Double hitbox1 = new Ellipse2D.Double(a, b, 50, 50);
public void checkiftouching() {
if (hitbox1.intersects(hitbox))
;
System.out.println("you won");
a = randomgenerator.nextInt(1220);
b = randomgenerator.nextInt(720);
repaint();
score = score + 1;
}
public void keyPressed(KeyEvent e) {
if (e.getKeyCode() == KeyEvent.VK_LEFT) {
x = x - run;
hitbox.setFrame(x, getY(), getWidth(), getHeight());
hitbox1.setFrame(a, b, 50, 50);
repaint();
// System.out.println(x);
} else if (e.getKeyCode() == KeyEvent.VK_RIGHT) {
x = x + run;
hitbox.setFrame(x, getY(), getWidth(), getHeight());
hitbox1.setFrame(a, b, 50, 50);
repaint();
// System.out.println(x);
} else if (e.getKeyCode() == KeyEvent.VK_UP) {
y = y - run;
hitbox.setFrame(getX(), y, getWidth(), getHeight());
hitbox1.setFrame(a, b, 50, 50);
repaint();
// System.out.println(y);
} else if (e.getKeyCode() == KeyEvent.VK_DOWN) {
y = y + run;
hitbox.setFrame(getX(), y, getWidth(), getHeight());
hitbox1.setFrame(a, b, 50, 50);
repaint();
// System.out.println(y);
}
}
@Override
public void keyTyped(KeyEvent e) {
// TODO Auto-generated method stub
}
@Override
public void keyReleased(KeyEvent e) {
// TODO Auto-generated method stub
}
}
答案 0 :(得分:3)
您会注意到
public void checkiftouching(){
永远不会打电话给。此外,这个if语句最后有一个分号,所以它的确很少。
if (hitbox1.intersects(hitbox));
始终使用完整方括号{ .. }
如果您使用IDE,它应该为您突出显示这些错误。