Question

我想列出不是经理的员工名单......

如果您有更好的查询，请查看以下两个查询...

查询1：

SELECT Empno, Ename, Job, Sal
FROM Emp
WHERE Empno NOT IN (SELECT NVL(MGR,0) FROM Emp)

查询2：

SELECT Empno, Ename, Job, Sal
FROM Emp
WHERE Empno NOT IN (SELECT DISTINCT MGR FROM Emp WHERE MGR IS NOT NULL)

Answer 1

这可能会更快，具体取决于索引的字段：

select x.empno, x.ename, x.job, x.sal
  from emp x
  left join emp y
    on x.empno = y.mgr
 where y.mgr is null

使用具有相同表格的外部联接并过滤行中empno永远不会作为表格的mgr列中的值显示的行。

Answer 2

使用oracle特定功能：

select Empno, Ename, Job, Sal from Emp
where CONNECT_BY_ISLEAF = 1
start with MGR is null
connect by prior Empno = MGR;

有关如何使用它的示例，请参阅http://sqlfiddle.com/#!4/858e0/3

但如果没有经理层级更容易：

SELECT Empno, Ename, Job, Sal FROM Emp WHERE MGR IS NOT NULL

Answer 3

从emp a中选择* 哪里不存在（从emp中选择1，其中manager_id = a.emp_id）;

以上sql将找到所有不是经理的员工，并且存在具有更好性能但不在

中的功能

Answer 4

检查以下内容：

SELECT E.LAST_NAME,E.EMPLOYEE_ID FROM EMPLOYEES EWHERE EMPLOYEE_ID not in 
   (SELECT MANAGER_ID FROM EMPLOYEES where MANAGER_ID is not null)

Answer 5

SELECT * FROM employees
WHERE id <> managerid

Answer 6

这是涵盖所有情况的最佳解决方案

select e.name
  from employees as e
  left join employees as m
    on e.id = m.managerId
 where m.managerId is null

Answer 7

尝试此查询将起作用

选择Empno，Ename，Job，Sal 来自Emp 工作在哪里！='经理'

个

选择Empno，Ename，Job，Sal 来自Emp 工作不像“经理”的地方

Answer 8

let audio = new Audio()

class AudioContainer extends Component {
    constructor (props) {
        super(props);
        this.state = {
            images: [],
            index: 0,
            checkedItems: new Map(),
            correct: false,
            isPlaying: false,
            error: false
        };

    }


onPlayHandler = () => {
        audio.src = this.props.data[this.state.index].audio
        audio.play();
        this.setState({
            isPlaying: true
        });
    };

    onPauseHandler = () => {
        audio.src = this.props.data[this.state.index].audio
        //let aud = new Audio(this.props.data[this.state.index].audio);
        audio.pause();
        //aud.setAttribute("ref", `${this.myRef}`);
        this.setState({
            isPlaying: false
        });
        //this.refs.audio.pause(); 
        //x.pause(); 
        //console.log(aud)
    };

不是经理的员工名单

8 个答案: