在相关问题的一些答案中,我可以看到gdb 7.3应该支持至少使用' info threads'来显示线程名称。命令。 但我甚至没有那么奢侈。请帮助我理解我做错了什么。
我用于测试的示例代码:
#include <stdio.h>
#include <pthread.h>
#include <sys/prctl.h>
static pthread_t ta, tb;
void *
fx (void *param)
{
int i = 0;
prctl (PR_SET_NAME, "Mythread1", 0, 0, 0);
while (i < 1000)
{
i++;
printf ("T1%d ", i);
}
}
void *
fy (void *param)
{
int i = 0;
prctl (PR_SET_NAME, "Mythread2", 0, 0, 0);
while (i < 100)
{
i++;
printf ("T2%d ", i);
}
sleep (10);
/* generating segmentation fault */
int *p;
p = NULL;
printf ("%d\n", *p);
}
int
main ()
{
pthread_create (&ta, NULL, fx, 0);
pthread_create (&tb, NULL, fy, 0);
void *retval;
pthread_join (ta, &retval);
pthread_join (tb, &retval);
return 0;
}
输出(使用由分段错误生成的核心转储)
(gdb) core-file core.14001
[New LWP 14003]
[New LWP 14001]
[Thread debugging using libthread_db enabled]
Using host libthread_db library "/lib/libthread_db.so.1".
Core was generated by `./thread_Ex'.
Program terminated with signal SIGSEGV, Segmentation fault.
#0 0x08048614 in fy (param=0x0) at thread_Ex.c:30
30 printf("%d\n",*p);
(gdb) info threads
Id Target Id Frame
2 Thread 0xb77d76c0 (LWP 14001) 0x00b95424 in __kernel_vsyscall ()
* 1 Thread 0xb6dd5b70 (LWP 14003) 0x08048614 in fy (param=0x0) at thread_Ex.c:30
(gdb) bt
#0 0x08048614 in fy (param=0x0) at thread_Ex.c:30
#1 0x006919e9 in start_thread () from /lib/libpthread.so.0
#2 0x005d3f3e in clone () from /lib/libc.so.6
(gdb) thread apply all bt
Thread 2 (Thread 0xb77d76c0 (LWP 14001)):
#0 0x00b95424 in __kernel_vsyscall ()
#1 0x006920ad in pthread_join () from /lib/libpthread.so.0
#2 0x080486a4 in main () at thread_Ex.c:50
Thread 1 (Thread 0xb6dd5b70 (LWP 14003)):
#0 0x08048614 in fy (param=0x0) at thread_Ex.c:30
#1 0x006919e9 in start_thread () from /lib/libpthread.so.0
#2 0x005d3f3e in clone () from /lib/libc.so.6
(gdb) q
正如您所看到的,我无法看到我设置的任何线程名称。什么可能是错的?
注意: 我正在使用gdb版本7.7(使用没有特殊选项下载和编译) 用于编译和编译的命令安装gdb:./ configure&amp;&amp;制造&amp;&amp; make install
答案 0 :(得分:1)
据我所知,核心转储中不存在线程名称。
如果它们以某种方式可用,请提交gdb错误。
答案 1 :(得分:0)
我在CentOS6.5上显示线程名称,但未在CentOS6.4上显示。