我遇到这个例外的问题:
type Exception report
message An exception occurred processing JSP page /home/index.jsp at line 54
description The server encountered an internal error that prevented it from fulfilling this request.
exception
org.apache.jasper.JasperException: An exception occurred processing JSP page /home/index.jsp at line 54
51: <link rel="shortcut icon" href="../assets/ico/favicon.png">
52: <style type="text/css">
53: <%
54: HashMap<String,Object> background = com.controlj.green.definitions.Utilities.getBackground();
55: String background_image = "";
56: if(!background.isEmpty()){
57: background_image = "data:image/png;base64," + background.get("bytes").toString();
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:568)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:455)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
com.controlj.green.servlets.Index.doGet(Index.java:51)
javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
root cause
javax.servlet.ServletException: java.lang.IncompatibleClassChangeError: Found class com.mysql.jdbc.Statement, but interface was expected
org.apache.jasper.runtime.PageContextImpl.doHandlePageException(PageContextImpl.java:912)
org.apache.jasper.runtime.PageContextImpl.handlePageException(PageContextImpl.java:841)
org.apache.jsp.home.index_jsp._jspService(index_jsp.java:83)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
com.controlj.green.servlets.Index.doGet(Index.java:51)
javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
root cause
java.lang.IncompatibleClassChangeError: Found class com.mysql.jdbc.Statement, but interface was expected
com.controlj.green.definitions.Utilities.getBackground(Utilities.java:172) org.apache.jsp.home.index_jsp._jspService(index_jsp.java:68)
org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:432)
org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:390)
org.apache.jasper.servlet.JspServlet.service(JspServlet.java:334)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
com.controlj.green.servlets.Index.doGet(Index.java:51)
javax.servlet.http.HttpServlet.service(HttpServlet.java:621)
javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
note The full stack trace of the root cause is available in the Apache Tomcat/7.0.42 logs.
Apache Tomcat/7.0.42
我真的不知道第54行的错误。
显然这称之为: com.controlj.green.definitions.Utilities.getBackground();
是:
import java.util.*;
public static HashMap<String,Object> getBackground() throws SQLException, ClassNotFoundException, IOException {
if(establishConnection()){
Statement st = (Statement) con.createStatement();
rs = st.executeQuery("select bytes from connection_string");
ResultSetMetaData md = (ResultSetMetaData) rs.getMetaData();
int columns = md.getColumnCount();
HashMap<String,Object> list = new HashMap<String,Object>();
if (rs.next()) {
for(int i=1; i<=columns; ++i){
list.put(md.getColumnName(i),rs.getObject(i));
}
}
return list;
}else{
return null;
}
}
这可能有什么问题?
感谢。
答案 0 :(得分:1)
来自堆栈跟踪,
根本原因javax.servlet.ServletException: java.lang.IncompatibleClassChangeError:找到类
com.mysql.jdbc.Statement,但预期接口
为什么要在这里投射statement
课程,
Statement st = (Statement) con.createStatement();
它必须是,
Statement st =con.createStatement();
期望con
成为连接对象
<强>更新强>
根据您分享错误导入的错误,
错误的课程
import com.mysql.jdbc.Connection;
import com.mysql.jdbc.Statement;
应该是
import java.sql.Connection;
import java.sql.Statement;
希望这有帮助
答案 1 :(得分:0)
什么是骗局
Statement st = (Statement) con.createStatement();
来自哪里。无论如何,你不需要演员声明。
答案 2 :(得分:0)
我认为我们不需要像你在这里那样进行投射
Statement st = (Statement) con.createStatement();
只要con
是java.sql.Connection
或者您可能正在使用某些旧版mysql-connector.jar
尝试将其替换为某些newer version并再次导入连接语句
答案 3 :(得分:0)
你从哪里获得连接?全局变量?,我会尝试更改你准备好的语句,就像这样。我不知道你是否在某种程度上控制了异常以便顺便关闭连接。
PreparedStatement ps = null;
try{
ps = conn.prepareStatement("select bytes from connection_string");
ps.executeQuery();
} catch(Exception ex){
System.out.println("");
} finally {
try{
if(ps!=null){
ps.close();
}
if(conn!=null){
conn.close();
}
} catch(Exception ex){
System.out.println("");
}
}