我在图像中有很多形状,我想在数组中保存它们的轮廓。 我的意思是我想要数组1中形状1的轮廓坐标,数组2中的形状2的坐标...
如果有两种形状,我如何使用它们的坐标绘制它们之间的最短线?
例如,我在图像上进行了许多操作后得到了这个结果
找到轮廓后
:
所以我需要每个形状轮廓的坐标来计算它们之间的最短距离
答案 0 :(得分:3)
您可以参考this link& this wiki用于检测图像中的轮廓。
要从两个形状中找到最小距离,请执行以下步骤:
以下是此算法的EMGUCV实现。
private void button2_Click(object sender, EventArgs e)
{
Image<Gray, byte> Img_Scene_Gray = Img_Source_Bgr.Convert<Gray, byte>();
Image<Bgr, byte> Img_Result_Bgr = Img_Source_Bgr.Copy();
LineSegment2D MinIntersectionLineSegment = new LineSegment2D();
Img_Scene_Gray = Img_Scene_Gray.ThresholdBinary(new Gray(10), new Gray(255));
#region Finding Contours
using (MemStorage Scene_ContourStorage = new MemStorage())
{
for (Contour<Point> Contours_Scene = Img_Scene_Gray.FindContours(CHAIN_APPROX_METHOD.CV_CHAIN_APPROX_SIMPLE,
RETR_TYPE.CV_RETR_EXTERNAL, Scene_ContourStorage); Contours_Scene != null; Contours_Scene = Contours_Scene.HNext)
{
if (Contours_Scene.Area > 25)
{
if (Contours_Scene.HNext != null)
{
MinIntersectionLine(Contours_Scene, Contours_Scene.HNext, ref MinIntersectionLineSegment);
Img_Result_Bgr.Draw(MinIntersectionLineSegment, new Bgr(Color.Green), 2);
}
Img_Result_Bgr.Draw(Contours_Scene, new Bgr(Color.Red), 1);
}
}
}
#endregion
imageBox1.Image = Img_Result_Bgr;
}
void MinIntersectionLine(Contour<Point> a, Contour<Point> b,ref LineSegment2D Line)
{
double MinDist = 10000000;
for (int i = 0; i < a.Total; i++)
{
for (int j = 0; j < b.Total; j++)
{
double Dist = Distance_BtwnPoints(a[i], b[j]);
if (Dist < MinDist)
{
Line.P1 = a[i];
Line.P2 = b[j];
MinDist = Dist;
}
}
}
}
double Distance_BtwnPoints(Point p, Point q)
{
int X_Diff = p.X - q.X;
int Y_Diff = p.Y - q.Y;
return Math.Sqrt((X_Diff * X_Diff) + (Y_Diff * Y_Diff));
}