Question

我试图获取JSONP数据，以便我可以在javascript中解析它。我有一些我可以解析的模拟数据，如下所示：

var employees = [
    { "Cost": 50, "Date": "2014-05-25T00:00:00", "Distance": "5k", "Id": "137", "Location": "Salt Lake City", "Name": "Employee 1", "Type": "normal" },
    { "Cost": 50, "Date": "2014-05-25T00:00:00", "Distance": "5k", "Id": "138", "Location": "Provo", "Name": "Employee 2", "Type": "normal" },
    { "Cost": 50, "Date": "2014-05-25T00:00:00", "Distance": "5k", "Id": "139", "Location": "Ogden", "Name": "Employee 3", "Type": "normal" }
];

但是当我尝试使用JSONP从另一台服务器上的RESTful API获取相同的数据时，它不起作用。我希望能够以与模拟数据相同的格式获取数据。我不知道我请求它的方式是否错误，但这是我怀疑的，因为数据存在，并且采用JSONP格式。以下是我要求它的方式：

var employees;
var url = 'http://marketing.wasatchtechies.com/api/JSONraces/callback=?';

$.ajax({
    type: 'GET',
    url: url,
    async: true,
    contentType: "application/json",
    dataType: 'jsonp',
    success: function (data) {
        employees = data;
    },
    error: function (err) {
        // nothing
    }
});

谢谢你看看。

修改：当您点击此链接http://marketing.wasatchtechies.com/api/JSONraces?callback=foobar时，您会收到以下信息：

foobar([{"id":137,"name":"JE Cosgriff Tiger Trot","location":"Salt Lake City","date":"2014-05-25T00:00:00","url":"http://www.utahrunning.com/events/race/ref/JE-Cosgriff-Tiger-Trot","distance":"5k","cost":"50        ","type":"normal"},{"id":138,"name":"Race for Grief Event","location":"West Bountiful","date":"2014-05-26T00:00:00","url":"http://www.utahrunning.com/events/race/ref/Race-for-Infant--Pregnancy-Loss---10K-run--2-mile-awareness-walk","distance":"5k","cost":"45        ","type":"normal"},{"id":139,"name":"Heber Valley Memorial Run","location":"Heber City","date":"2014-05-26T00:00:00","url":"http://www.utahrunning.com/events/race/ref/Heber-Valley-Memorial-Run","distance":"5k, mile","cost":"35        ","type":"glow"}]);

Answer 1

您只需在回调中设置它：

var employees;

$.ajax({
  type: 'GET',
  url: url,
  contentType: "application/json",
  dataType: 'jsonp',
  success: function(data) {
    employees = data; 
  }
});

Answer 2

您缺少回调方法

ajax请求中的成功和错误方法。像这样的东西

var employees = $.ajax({
    type: 'GET',
    url: url,
    async: false,
    contentType: "application/json",
    dataType: 'jsonp',
    success: function(result) {
        // access your mock data in result
    },
    error: function(err) {
         // acces err object to handle the error
    }
});

如何将JSONP数据作为javascript对象获取

2 个答案: