Question

我在将复杂网址传递给file_get_html时遇到问题当我尝试使用此代码时

<?php

require_once("$_SERVER[DOCUMENT_ROOT]/dom/simple_html_dom.php");
$base = $_GET['url'];
//file_get_contents() reads remote webpage content
    $html_base = file_get_html("http://www.realestateinvestar.com.au/ME2/dirmod.asp?sid=1A0FFDB3E8CD48909120C118D03F6016&nm=&type=news&mod=News&mid=9A02E3B96F2A415ABC72CB5F516B4C10&tier=3&nid=C67A9DD2C0144B9EB41DB58365C05927");

foreach($html_base->find('p') as $td) {
 echo $td;
}

?>

它有效

但是如果我尝试通过mysite.com/goget.php?url=http://www.realestateinvestar.com.au/ME2/dirmod.asp?sid=1A0FFDB3E8CD48909120C118D03F6016&nm=&type=news&mod=News&mid=9A02E3B96F2A415ABC72CB5F516B4C10&tier=3&nid=C67A9DD2C0144B9EB41DB58365C05927

将url作为变量传递

<?php

require_once("$_SERVER[DOCUMENT_ROOT]/dom/simple_html_dom.php");
$base = $_GET['url'];
//file_get_contents() reads remote webpage content
    $html_base = file_get_html($base);

foreach($html_base->find('p') as $td) {
 echo $td;
}

?>

返回空白页。

任何帮助？

Answer 1

使用urlencode()：

"mysite.com/goget.php?url="
.urlencode("http://www.realestateinvestar.com.au/ME2/dirmod.asp?sid=1A0FFDB3E8CD48909120C118D03F6016&nm=&type=news&mod=News&mid=9A02E3B96F2A415ABC72CB5F516B4C10&tier=3&nid=C67A9DD2C0144B9EB41DB58365C05927")

简单的DOM file_get_html返回空页面

1 个答案: