Question

我正在尝试创建一个计算机与计算机猜谜游戏，问题是计算机会猜两次相同的数字。我尝试使用变量.remove()，但计算机仍会猜测变量的位置，所以我会收到错误。我将代码还原到了它的工作位置。

print 'Get ready for some action!'
time.sleep(1)
firstname = raw_input('Enter in a name for computer 1... ')
time.sleep(1)
secondname = raw_input('Enter in a name for computer 2... ')
time.sleep(1)
howlittle = int(raw_input('Enter in the min... '))
time.sleep(1)
howmuch = int(raw_input('Enter in the max... '))
computernumber = random.randint(howlittle,howmuch)
print firstname + 'choses %s as its lucky number.' %computernumber
time.sleep(1)
print '%s is thinking...'%secondname
time.sleep(1)
firsts=random.randint(howlittle,howmuch)
if firsts == computernumber:
    print 'The %s won!'%secondname
guessers = 0
computers=[]
while firsts != computernumber:
    guessers += 1
    if firsts == computernumber:
        print 'The computer won in %s guesses'%guessers
    elif firsts > computernumber:
        firsts = random.randint(howlittle,firsts)
        computers.append(firsts)
    elif firsts < computernumber:
        firsts = random.randint(firsts, howmuch)
        computers.append(firsts)
print secondname + " took %s guesses to guess the number" %guessers
print computers

我仍然在为它添加功能，但我只需要首先解决这个问题。谢谢！

Answer 1

在您的elif中添加if条件，以便：

如果number_guessed在computer_guesses_list中：再次生成一个随机数

Answer 2

问题可能是random.randint(a,b)在[a，b]中返回一个数字x，即a <= x <= b。

因此，在您的代码中，random.randint(howlittle,firsts)可能会返回firsts，请将其更改为random.randint(howlittle,firsts-1)

和random.randint(firsts,howmuch)到random.randint(firsts+1,howmuch)

您应该发布不起作用的代码。

如何在电脑猜谜游戏中删除用过的数字？

2 个答案: