Question

我在使用商店阅读我的php文件时遇到问题。我认为问题是php文件中的base64_encode命令。我解释一下。在我的PHP中，我采用sql代码的路径，之后，通过这条路径，我得到了真实的图像。在我需要将结果保存在一个数组中后，给sencha架构师。这是PHP代码：



require("db.php");
    session_start();
    $filepath='';
    $sql = "SELECT concat('C:/wamp/www/Tecnitalia_Optic/app/webroot/img/',folder) as Path, thumb as FileName FROM frames ";
    $result = array();
    if ($resultdb = $mysqli->query($sql)) {
    while($record = $resultdb->fetch_array()) {
        $filepath = $record['Path'];
        $nomeFile = $record['FileName'];
        $mimetype = pathinfo($nomeFile, PATHINFO_EXTENSION);
        $filedata=filesize($filepath."/".$nomeFile);
        header('Content-Type: '.$mimetype);
        header('Content-Disposition: attachment; filename="'.$nomeFile.'"');
        header('Content-Transfer-Encoding: binary');
        header('Content-Length: '.sprintf('%d', $filedata));
        header('Expires: 0');
        //readfile($filepath."/".$nomeFile);
        $recordnew = readfile($filepath."/".$nomeFile);
        $result[] = $recordnew;
    }
    $resultdb->close();
    }
    //count total records from table for paging
    $sql = "SELECT count(*) as num FROM frames ";
    $total = 0;
    if ($resultdb = $mysqli->query($sql)) {
    $record = $resultdb->fetch_assoc();
    $total = $record['num'];
    $resultdb->close();
    }
    //send back information to sencha architect touch
    echo json_encode(array(
    "success" => $mysqli->connect_errno == 0,
    "total" => $total,
    "data" => base64_encode($result)
    )); 
    /* close connection */
    $mysqli->close();

require("db.php"); session_start(); $filepath=''; $sql = "SELECT concat('C:/wamp/www/Tecnitalia_Optic/app/webroot/img/',folder) as Path, thumb as FileName FROM frames "; $result = array(); if ($resultdb = $mysqli->query($sql)) { while($record = $resultdb->fetch_array()) { $filepath = $record['Path']; $nomeFile = $record['FileName']; $mimetype = pathinfo($nomeFile, PATHINFO_EXTENSION); $filedata=filesize($filepath."/".$nomeFile); header('Content-Type: '.$mimetype); header('Content-Disposition: attachment; filename="'.$nomeFile.'"'); header('Content-Transfer-Encoding: binary'); header('Content-Length: '.sprintf('%d', $filedata)); header('Expires: 0'); //readfile($filepath."/".$nomeFile); $recordnew = readfile($filepath."/".$nomeFile); $result[] = $recordnew; } $resultdb->close(); } //count total records from table for paging $sql = "SELECT count(*) as num FROM frames "; $total = 0; if ($resultdb = $mysqli->query($sql)) { $record = $resultdb->fetch_assoc(); $total = $record['num']; $resultdb->close(); } //send back information to sencha architect touch echo json_encode(array( "success" => $mysqli->connect_errno == 0, "total" => $total, "data" => base64_encode($result) )); /* close connection */ $mysqli->close();

之后，在SA中我创建了一个模型，其中一个字段的类型为auto。在我用模型创建了一个Json Store链接之后，商店就这样说：MyJsonReader无法读取数据。在浏览器中打开：api / frames.php

这是我的sencha架构师代码：

模型和商店

HI Zoltan感谢您的回复。你能用一个例子来解释你说的是什么？我取消了base64_encode命令但是我可以做什么？ Inside Architect Touch或在php文件中？

Answer 1

我认为您不需要对结果进行base64编码，但需要JSON编码来递归编码返回值（即数据par也应该是json编码的值）。

sencha Architect（Touch） - 商店不读我的php文件

1 个答案: