Question

我根据经度和纬度值获得了当前位置，然后我还使用Annotation在Google地图上获得了多个位置。现在我想得到基于地址（即街道，城市和县）的经度和纬度值。需要一些指导如何实现。

直到现在，这是我尝试过的： -

#import "ViewController.h"

@interface ViewController ()

@end

@implementation ViewController
@synthesize streetField = _streetField, cityField = _cityField, countryField = _countryField, fetchCoordinatesButton = _fetchCoordinatesButton, nameLabel = _nameLabel, coordinatesLabel = _coordinatesLabel;
@synthesize geocoder = _geocoder;


- (void)viewDidLoad
{

    [super viewDidLoad];
    _streetField.delegate=self;
    _cityField.delegate=self;
    _countryField.delegate=self;

    // Do any additional setup after loading the view, typically from a nib.
}

- (IBAction)fetchCoordinates:(id)sender {
    NSLog(@"Fetch Coordinates");
    if (!self.geocoder) {
          NSLog(@"Geocdoing");
        self.geocoder = [[CLGeocoder alloc] init];
    }

    NSString *address = [NSString stringWithFormat:@"%@ %@ %@", self.streetField.text, self.cityField.text, self.countryField.text];
    NSLog(@"GET Addres%@",address);

    self.fetchCoordinatesButton.enabled = NO;

    [self.geocoder geocodeAddressString:address completionHandler:^(NSArray *placemarks, NSError *error) {
          NSLog(@"Fetch Gecodingaddress");
        if ([placemarks count] > 0) {
            CLPlacemark *placemark = [placemarks objectAtIndex:0];

             NSLog(@"GET placemark%@",placemark);

            CLLocation *location = placemark.location;

            NSLog(@"GET location%@",location);

            CLLocationCoordinate2D coordinate = location.coordinate;


            self.coordinatesLabel.text = [NSString stringWithFormat:@"%f, %f", coordinate.latitude, coordinate.longitude];

            NSLog(@"CoordinatesLabel%@",self.coordinatesLabel.text);


            if ([placemark.areasOfInterest count] > 0) {
                NSString *areaOfInterest = [placemark.areasOfInterest objectAtIndex:0];
                self.nameLabel.text = areaOfInterest;
                NSLog(@"NameLabe%@",self.nameLabel.text);
            }
        }

        self.fetchCoordinatesButton.enabled = YES;
    }];
}

- (void)didReceiveMemoryWarning
{
    [super didReceiveMemoryWarning];
    // Dispose of any resources that can be recreated.
}
-(BOOL)textFieldShouldReturn:(UITextField *)textField
{
    [textField resignFirstResponder];
    return YES;
}
@end

上面的代码不能给我经纬度。需要帮助我在这里做错了什么，或者我是否缺少某些东西。

先谢谢。

Answer 1

修改：

在iOS8更新中使用此检查之前

NSLocationAlwaysUsageDescription NSLocationWhenInUseUsageDescription

这是为了获得基于纬度和长度的用户区域，如街道名称，州名，国家。

-(CLLocationCoordinate2D) getLocationFromAddressString: (NSString*) addressStr { double latitude = 0, longitude = 0; NSString *esc_addr = [addressStr stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]; NSString *req = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", esc_addr]; NSString *result = [NSString stringWithContentsOfURL:[NSURL URLWithString:req] encoding:NSUTF8StringEncoding error:NULL]; if (result) { NSScanner *scanner = [NSScanner scannerWithString:result]; if ([scanner scanUpToString:@"\"lat\" :" intoString:nil] && [scanner scanString:@"\"lat\" :" intoString:nil]) { [scanner scanDouble:&latitude]; if ([scanner scanUpToString:@"\"lng\" :" intoString:nil] && [scanner scanString:@"\"lng\" :" intoString:nil]) { [scanner scanDouble:&longitude]; } } } CLLocationCoordinate2D center; center.latitude=latitude; center.longitude = longitude; NSLog(@"View Controller get Location Logitute : %f",center.latitude); NSLog(@"View Controller get Location Latitute : %f",center.longitude); return center; }

根据你的项目
在viewdidload方法或某个地方调用这样的方法
[self getLocationFromAddressString:@"chennai"];

只需在浏览器中传递此内容即可 http://maps.google.com/maps/api/geocode/json?sensor=false&address=chennai

你将拥有lat和lon的json格式

http://maps.google.com/maps/api/geocode/json?sensor=false&address=@"your city name here" NSString *address = [NSString stringWithFormat:@"http://maps.google.com/maps/api/geocode/json?sensor=false&address=%@ %@ %@", self.streetField.text, self.cityField.text, self.countryField.text];

这种方法的用法......

CLLocationCoordinate2D center; center=[self getLocationFromAddressString:@"uthangarai"]; double latFrom=&center.latitude; double lonFrom=&center.longitude; NSLog(@"View Controller get Location Logitute : %f",latFrom); NSLog(@"View Controller get Location Latitute : %f",lonFrom);

Answer 2

<强>夫特

public func getLocationFromAddress(address : String) -> CLLocationCoordinate2D {
        var lat : Double = 0.0
        var lon : Double = 0.0

        do {

            let url = String(format: "https://maps.google.com/maps/api/geocode/json?sensor=false&address=%@", (address.addingPercentEncoding(withAllowedCharacters: .urlPathAllowed)!))
            let result = try Data(contentsOf: URL(string: url)!)
            let json = JSON(data: result)

            lat = json["results"][0]["geometry"]["location"]["lat"].doubleValue
            lon = json["results"][0]["geometry"]["location"]["lng"].doubleValue

        }
        catch let error{
            print(error)
        }

        return CLLocationCoordinate2D(latitude: lat, longitude: lon)
    }

我使用了SwiftyJSON，但您可以根据需要解析JSON响应

Answer 3

试试这个，

NSString *address = [NSString stringWithFormat:@"%@,%@,%@", self.streetField.text, self.cityField.text,self.countryField.text];    

[self.geocoder geocodeAddressString:address completionHandler:^(NSArray *placemarks, NSError *error)
 {
     if(!error)
     {
         CLPlacemark *placemark = [placemarks objectAtIndex:0];
         NSLog(@"%f",placemark.location.coordinate.latitude);
         NSLog(@"%f",placemark.location.coordinate.longitude);
         NSLog(@"%@",[NSString stringWithFormat:@"%@",[placemark description]]);
     }
     else
     {
         NSLog(@"There was a forward geocoding error\n%@",[error localizedDescription]);
     }
 }
 ];

Answer 4

- (IBAction)forwardButton:(id)sender
{
    if([self.address.text length])
    {
        NSString *place = self.address.text;
        CLGeocoder *geocoder = [[CLGeocoder alloc] init];
        __unsafe_unretained RTGeoCoderViewController *weakSelf = self;
        [geocoder geocodeAddressString:place completionHandler:^(NSArray* placemarks, NSError* error)
         {
             NSLog(@"completed");
             if ( error )
             {
                 NSLog(@"error = %@", error );
                 dispatch_async(dispatch_get_main_queue(),
                                ^{
                                    UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Error" message:[self errorMessage:error.code] delegate:nil cancelButtonTitle:nil otherButtonTitles:@"OK", nil];
                                    [alert show];
                                });
             }
             else
             {
                NSLog(@"%@",placemarks);
             }
         }];
    }
}

Answer 5

试试这个

 - (void)getAddressFromAdrress:(NSString *)address withCompletationHandle:(void (^)(NSDictionary *))completationHandler {   


                CLGeocoder *geoCoder = [[CLGeocoder alloc] init];  
            //Get the address through geoCoder  
            [geoCoder geocodeAddressString:address   completionHandler:^(NSArray *placemarks, NSError *error) {  


                if ([placemarks count] > 0 && !error) {

                    //get the address from placemark
                    CLPlacemark *placemark = [placemarks objectAtIndex:0];
                    NSString *locatedAt = [[placemark.addressDictionary valueForKey:@"FormattedAddressLines"] componentsJoinedByString:@", "];
                    CLLocation *location = placemark.location;
                    CLLocationCoordinate2D coordinate = location.coordinate;
                    _latitudeUserLocation  = coordinate.latitude;
                    _longitudeUserLocation = coordinate.longitude;
                    NSString *postalCode   =  placemark.addressDictionary[(NSString*)kABPersonAddressZIPKey];
                    if (postalCode == nil) postalCode = @"";
                    if (locatedAt == nil)  locatedAt  = @"";
                    NSDictionary *dictionary = [NSDictionary dictionaryWithObjectsAndKeys:
                                                postalCode               ,kPostalCode,
                                                locatedAt                ,kFullAddress,
                                                nil];
                    completationHandler(dictionary);

                } else {

                    completationHandler(nil);
                }
            }];
}

使用iOS中的Geocoder类，根据地址获取纬度和经度

5 个答案: