SQL语法验证

Question

以下是我的数据库结构：

以下是我的TimeSlot.php的片段：

    public $hasMany = array(
    'Response' => array(
        'className' => 'Response',
        'foreignKey' => 'time_slot_id`'
    )
);

和Response.php：

   public $belongsTo = array(
    'TimeSlot' => array(
        'className' => 'TimeSlot',
        'foreignKey' => 'time_slot_id'
    )
);

当我将此行添加到Meetings Controller中的操作时

  $this->loadModel("TimeSlot");
  $time_slot = $this->TimeSlot->find("first");
  debug($time_slot);

结果为：

   Database Error
   Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL    syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '`.`responses` AS `Response` WHERE `Response`.`time_slot_id` = (1)' at line 1

   SQL Query: SELECT `Response`.`id`, `Response`.`invitee_id`, `Response`.`time_slot_id`, `Response`.`time_slot_id`` FROM `meetingscheduler`.`responses` AS `Response` WHERE `Response`.`time_slot_id` = (1)

我对我的代码有什么不妥之处。但我认为它与TimeSlot和Response Models之间存在关系，因为一旦我忽略了关系，它的工作正常。

Answer 1

这里有一个额外的刻度：

.`time_slot_id``
             ^^^