Question

我有一个NSTextField，我要求用户输入IPv4格式的字符串或www.example.com等域名。目前，我的代码是：

@IBAction func verifyTarget(sender: NSTextFieldCell) {
    var txtTarget: NSTextFieldCell = sender

    var strRawTarget: String? = txtTarget.stringValue
    println("Input: " + strRawTarget!)
    var URLTarget: NSURL?

    URLTarget = NSURL.URLWithString(strRawTarget)
    if URLTarget {
        println("URL \(URLTarget) is valid!")
    }
    else {
        println("URL \(strRawTarget) is not valid!")
    }
}

一些示例输出：

Input: 
URL  is valid!
Input: adsfasdf
URL adsfasdf is valid!
Input: afe12389hfs. . afopadsf
URL afe12389hfs. . afopadsf is not valid!
Input: 192.292.111.3
URL 192.292.111.3 is valid!
Input: 0.a.0.a
URL 0.a.0.a is valid!
Input: %2
URL %2 is not valid!
Input: %20
URL %20 is valid!

我做错了吗？

Answer 1

检查Swift中的IP地址是IPv4还是IPv6

func validateIpAddress(ipToValidate: String) -> Bool {

    var sin = sockaddr_in()
    var sin6 = sockaddr_in6()

    if ipToValidate.withCString({ cstring in inet_pton(AF_INET6, cstring, &sin6.sin6_addr) }) == 1 {
        // IPv6 peer.
        return true
    }
    else if ipToValidate.withCString({ cstring in inet_pton(AF_INET, cstring, &sin.sin_addr) }) == 1 {
        // IPv4 peer.
        return true
    }

    return false;
}

Answer 2

NSURL.URLWithString根据解释这些不那么可读的文档中列出的相对或绝对地址的条件，评估您传递的URL字符串：RFC 2396，{{3 }和1738。也就是说，您希望验证的内容只是NSURL可以处理的一小部分。您最好使用RegEx或两个，可能来自1808：

@IBAction func verifyTarget(sender: NSTextFieldCell) {
    var txtTarget: NSTextFieldCell = sender

    var strRawTarget: String? = txtTarget.stringValue
    println("Input: " + strRawTarget!)

    let validIpAddressRegex = "^(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$"
    let validHostnameRegex = "^(([a-zA-Z0-9]|[a-zA-Z0-9][a-zA-Z0-9\\-]*[a-zA-Z0-9])\\.)*([A-Za-z0-9]|[A-Za-z0-9][A-Za-z0-9\\-]*[A-Za-z0-9])$"

    if strRawTarget == nil {
        println("no input!")
    } else if strRawTarget!.rangeOfString(validIpAddressRegex, options: .RegularExpressionSearch) {
        println("\(strRawTarget) is a valid IP address")
    } else if strRawTarget!.rangeOfString(validHostnameRegex, options: .RegularExpressionSearch) {
        println("\(strRawTarget) is a valid hostname")
    } else {
        println("\(strRawTarget) is not valid")
    }
}

Answer 3

来自@Alin的代码，形式更紧凑：

extension String {
func isIPv4() -> Bool {
    var sin = sockaddr_in()
    return self.withCString({ cstring in inet_pton(AF_INET, cstring, &sin.sin_addr) }) == 1
}

func isIPv6() -> Bool {
    var sin6 = sockaddr_in6()
    return self.withCString({ cstring in inet_pton(AF_INET6, cstring, &sin6.sin6_addr) }) == 1
}

func isIpAddress() -> Bool { return self.isIPv6() || self.isIPv4() }
}

用法：

let ipv6 = "FE80:0000:0000:0000:0202:B3FF:FE1E:8329"
let ipv6Collapsed = "FE80::0202:B3FF:FE1E:8329"
let ipv4 = "19.117.63.126"

ipv6.isIpAddress()  //true
ipv6.isIPv6()       //true
ipv6.isIPv4()       //false

ipv6Collapsed.isIpAddress() //true
ipv6Collapsed.isIPv6()      //true
ipv6Collapsed.isIPv4()      //false

ipv4.isIpAddress()  //true
ipv4.isIPv6()       //false
ipv4.isIPv4()       //true

Answer 4

已基于@Nate Cook response更新为 Swift 5.1 。

@IBAction func verifyTarget(sender: NSTextFieldCell) {
    guard let strRawTarget = sender.stringValue else { print("no input!"); return }
    print("Input: " + strRawTarget)

    if strRawTarget.isValidIpAddress {
        print("\(strRawTarget) is a valid IP address")
    } else if strRawTarget.isValidHostname {
        print("\(strRawTarget) is a valid hostname")
    } else {
        print("\(strRawTarget) is not valid")
    }
}

struct Regex {
    private init() {}

    static let ipAddress = "^(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$"
    static let hostname = "^(([a-zA-Z0-9]|[a-zA-Z0-9][a-zA-Z0-9\\-]*[a-zA-Z0-9])\\.)*([A-Za-z0-9]|[A-Za-z0-9][A-Za-z0-9\\-]*[A-Za-z0-9])$"
}

extension String {
    var isValidIpAddress: Bool {
        return self.matches(pattern: Regex.ipAddress)
    }

    var isValidHostname: Bool {
        return self.matches(pattern: Regex.hostname)
    }

    private func matches(pattern: String) -> Bool {
        return self.range(of: pattern,
                          options: .regularExpression,
                          range: nil,
                          locale: nil) != nil
    }
}

Answer 5

@IBAction func verifyTarget(sender: NSTextFieldCell) -> Bool {
    let validIP = "^(([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])\\.){3}([0-9]|[1-9][0-9]|1[0-9]{2}|2[0-4][0-9]|25[0-5])$"
    if ((sender.stringValue.count == 0) || (sender.stringValue!.range(of: validIP, options: .regularExpression) == nil)) { 
        return false 
    }
    return true
}

Answer 6

新的网络框架为struct IPv4Address和struct IPv6Address提供了失败的初始化程序，它们很容易处理IP地址部分。使用所有正则表达式，使用正则表达式在IPv6中执行此操作都很困难。

很遗憾，我无法处理域名部分。

请注意，网络框架是最新的，因此可能会迫使您为最新的OS版本进行编译。

    import Network
let tests = ["192.168.4.4","fkjhwojfw","192.168.4.4.4","2620:3","2620::33"]

for test in tests {
    if let _ = IPv4Address(test) {
        debugPrint("\(test) is valid ipv4 address")
    } else if let _ = IPv6Address(test) {
        debugPrint("\(test) is valid ipv6 address")
    } else {
        debugPrint("\(test) is not a valid IP address")
    }
}

output:
"192.168.4.4 is valid ipv4 address"
"fkjhwojfw is not a valid IP address"
"192.168.4.4.4 is not a valid IP address"
"2620:3 is not a valid IP address"
"2620::33 is valid ipv6 address"

验证NSTextField中的字符串是否为有效的IP地址或域名

6 个答案: