Question

我有这个问题：

$querystr = "
SELECT  DISTINCT meta_value  FROM $wpdb->postmeta WHERE post_id IN(     
SELECT DISTINCT wpostmeta.post_id
FROM $wpdb->posts wposts, $wpdb->postmeta wpostmeta
WHERE wposts.ID = wpostmeta.post_id 
AND wpostmeta.meta_key  = 'Country' 
AND wpostmeta.meta_value  = 'UK' 
AND wposts.post_type = 'post' ) AND meta_key ='city'
 ";
 $cities = $wpdb->get_results($querystr, OBJECT);

<?php if ($cities ): ?>

 <?php global $post; ?>
 <?php foreach ($cities as $c): ?>    
 <?php echo $c->meta_value; ?> <br />    
 <?php endforeach; ?>

 <?php endif; ?>

我需要添加搜索＆＃34;类别名称＆＃34;或＆＃34;类别ID＆＃34; ...我该怎么办？

谢谢;）

_______________________________ -

感谢您的回复，我已经做了一些测试，但没有工作....无论如何，你能帮助我吗？：）

$term_id = "SELECT term_id FROM wp_terms WHERE name='foods' ";
$post_id = 'SELECT object_id FROM wp_terms_relationships 
WHERE term_taxonomy_id="$term_id->term_id';     
SELECT  DISTINCT meta_value  FROM $wpdb->postmeta WHERE post_id IN(     
SELECT DISTINCT wpostmeta.post_id
FROM $wpdb->posts wposts, $wpdb->postmeta wpostmeta
WHERE wposts.ID = wpostmeta.post_id 
AND wpostmeta.meta_key  = 'Country' 
AND wpostmeta.meta_value  = 'UK' 
AND wposts.post_type = 'post' ) AND meta_key ='city'
AND wp_posts.ID = '$post_id->object_id'

Answer 1

你错了，只是解释而不是确切的语法，你需要这样做。

    global $wpdb;
    $result = $wpdb->get_results("SELECT term_id FROM wp_terms WHERE name='foods'", OBJECT );
    $post_id = $wpdb->get_results("SELECT object_id FROM wp_terms_relationships 
    WHERE term_taxonomy_id='$result->term_id'", OBJECT );

现在，您可以通过这种方式将其传递给您的查询。

 AND wp_posts.ID = '$post_id->object_id'

WordPress与类别的Mysql查询

1 个答案: