Question

我有一个XML，如下所示。我需要创建一个以逗号分隔的AdvancedShipNotice值字符串。我们如何使用XPath而不使用XSLT？

注意：目前我正在循环throgh每个节点 - 但我正在寻找更好的方法

参考

XSLT: Generate comma-separated string from element values

XML

<root>
<AdvShipNotices>
    <AdvancedShipNotice>6D23513</AdvancedShipNotice>
    <StatusCD>OS</StatusCD>
    <CreatedOnDate>2014-03-28T11:08:16.750</CreatedOnDate>
    <TextilePlantCD>6D </TextilePlantCD>
</AdvShipNotices>
<AdvShipNotices>
    <AdvancedShipNotice>6D23514</AdvancedShipNotice>
    <StatusCD>OS</StatusCD>
    <CreatedOnDate>2014-03-28T11:08:16.750</CreatedOnDate>
    <TextilePlantCD>6D </TextilePlantCD>
</AdvShipNotices>
</root>

VB.Net

Dim objXML As New XmlDocument
Dim asnString As String
asnString = "<root>" & objASN.GetAdvShipNotices(containerScanParameter.PlantCD, containerScanParameter.UserID, , , "OS") & "</root>"
objXML.LoadXml(asnString)

Answer 1

您可以这样做：

StringReader reader = new StringReader( @"
  <doc>
    <e>a</e>
    <e>b</e>
    <e>c</e>
    <e>d</e>
    <e>e</e>
  </doc>".Trim()
  ) ;

XmlDocument xml = new XmlDocument() ;
xml.Load( reader ) ;

IEnumerable<string> texts = xml
                            .SelectNodes( "//*[text()]" )
                            .Cast<XmlNode>()
                            .Select( x => x.InnerText )
                            ;
string csv = String.Join( "," , texts ) ;

最后，csv应保留a,b,c,d,e。

根据XML的结构，您可能必须调整XPath外推以适应。

另一种方法使用XDocument。对于您的示例文档，这样的内容将起作用：

string xml =
@"<root>
    <AdvShipNotices>
      <AdvancedShipNotice>6D23513</AdvancedShipNotice>
      <StatusCD>OS</StatusCD>
      <CreatedOnDate>2014-03-28T11:08:16.750</CreatedOnDate>
      <TextilePlantCD>6D </TextilePlantCD>
    </AdvShipNotices>
    <AdvShipNotices>
      <AdvancedShipNotice>6D23514</AdvancedShipNotice>
      <StatusCD>OS</StatusCD>
      <CreatedOnDate>2014-03-28T11:08:16.750</CreatedOnDate>
      <TextilePlantCD>6D </TextilePlantCD>
    </AdvShipNotices>
  </root>" ;

XDocument doc     = XDocument.Parse( xml ) ;
string    csvFile = string.Join( Environment.NewLine ,
                      doc
                      .Root
                      .Elements()
                      .Select( e => string.Join( "," ,
                          e
                          .Elements()
                          .Select( c => c.Value )
                          )
                        )
                    ) ;

制作此文

6D23513,OS,2014-03-28T11:08:16.750,6D 
6D23514,OS,2014-03-28T11:08:16.750,6D

不使用XSLT从xml生成逗号分隔的字符串

1 个答案: