Question

我想将对象传递给过滤器，并希望在create action上使用after_filter更改对象属性。我只有产品型号有属性，比如名称，标题，价格。一旦添加了产品，我想设置使用after_filter更改价格，那么如何将创建的@product对象传递给过滤方法并更改价格。

class ProductsController < ApplicationController
  before_action :set_product, only: [:show, :edit, :update, :destroy]
  after_action  :change_price, only: [:create]    //what should be here..?


  # GET /products
  # GET /products.json
  def index
    @products = Product.all
  end

  # GET /products/1
  # GET /products/1.json
  def show
  end

  # GET /products/new
  def new
    @product = Product.new
  end

  # GET /products/1/edit
  def edit
  end

  # POST /products
  # POST /products.json
  def create
    @product = Product.new(product_params)

    respond_to do |format|
      if @product.save
        format.html { redirect_to @product, notice: 'Product was successfully created.' }
        format.json { render action: 'show', status: :created, location: @product }
      else
        format.html { render action: 'new' }
        format.json { render json: @product.errors, status: :unprocessable_entity }
      end
    end
  end

..
//rest of code
..
  private
    # Use callbacks to share common setup or constraints between actions.
    def set_product
      @product = Product.find(params[:id])
    end

    # Never trust parameters from the scary internet, only allow the white list through.
    def product_params
      params.require(:product).permit(:name, :category_id)
    end

    def change_name  
                                        //what should be here..? no condition say i want to change every price to 10$
    end
end

Answer 1

您应该使用模型回调after_create来实现此目标

Answer 2

实例变量在过滤后立即可用，无需任何操作。因为每个公共操作都创建了一个控制器实例。

但不要这样做。在操作中明确操作您操作的所有内容。过滤器适用于更通用的东西。

如何将对象传递到rails中的filters方法

2 个答案: