django搜索表单仅在提交表单时进行查询

时间:2014-06-23 05:11:28

标签: django search

这是我的观点

class SingleNewsView(ListView):
model = News
form_class = SearchForm
template_name = "single_news.html"



def get(self, request, pk, **kwargs):
    self.pk = pk

    self.pub_from = request.GET.get('pub_date_from',False)
    self.pub_to = request.GET.get('pub_date_to',False)
    self.crawlers = request.GET.get('crawler',False)

    print self.crawlers


    return super(SingleNewsView,self).get(request,pk, **kwargs)



def get_context_data(self, **kwargs):

    context = super(SingleNewsView,self).get_context_data(**kwargs)
    context["form"] = SearchForm#(self.request.GET)
    context["something"] = News.objects.filter(category_id=self.pk).filter(published_date__range=(self.pub_from,self.pub_to), crawler=self.crawlers)


    return context

当我进入页面时,由于未提供数据,因此不显示任何新闻。我希望最初显示所有新闻,当用户提交表单时,只需过滤工作。我怎么能这样做?

1 个答案:

答案 0 :(得分:1)

您应该添加get_queryset()方法,而不是在get_context_data()中进行过滤。您可以按以下方式添加方法

def get_queryset(self):
    qs = News.objects.filter(category_id=self.pk)
    #you can change this to just support one of the pub_from or pub_to
    if self.pub_from and self.pub_to :
        qs = qs.filter(published_date__range=(self.pub_from,self.pub_to)
    if self.crawler:
        qs = qs.filter(crawler=self.crawlers)