我有以下python代码 - 创建三个线程。但是在创建第一个线程后,控件似乎没有回来。输出是一个'而不是三个预期的'。工人职能有问题吗? Msglyr
是一个内部消息传递库。
#!/usr/bin/python
import thread
import time
import Msglyr
# Worker thread
def worker(num):
testchannel = Msglyr.Channel("TEST-ASYNC-ROUTER-DEALER-CHANNEL", Msglyr.mlr.ASYNC_ROUTER_DEALER, Msglyr.mlr.ASYNC_DEALER_WORKER)
testchannel.setEndPoint(Msglyr.mlr.ASYNC_DEALER_WORKER, "inproc://test-pt")
testchannel.setEndPoint(Msglyr.mlr.ASYNC_DEALER_CLIENT, "tcp://127.0.0.1:5558")
while True :
msg = Msglyr.Message()
testchannel.receive(msg)
if msg.getnumParts() > 0:
msg.setPart(msg.getnumParts() - 1, "Worker : " + str(num))
testchannel.send(msg)
# Creating three threads
try:
thread.start_new_thread( worker, (1, ) )
print '.'
time.sleep(2)
thread.start_new_thread( worker, (2, ) )
print '.'
time.sleep(2)
thread.start_new_thread( worker, (3, ) )
print '.'
time.sleep(2)
except:
print "Error: unable to start thread"
print 'Started threads'
while 1:
pass
答案 0 :(得分:1)
我不确定这是否真的是一个答案(不是你所期望的那样),但我不能做更多。我拿了你的代码并用
取代了工人# Worker thread
def worker(num):
i = 1
while True :
print("Thread", num, i);
i += 1
time.sleep(3)
一切顺利,我可以看到消息形成3个线程(1秒间隔...),我也看到3个点。我担心问题出在Msglyr
。