如何使用基于类的视图和django-filter的简单示例?

时间:2014-06-19 11:48:20

标签: django-views django-class-based-views django-filter

文档中的示例https://django-filter.readthedocs.org/en/latest/usage.html,我认为是基于函数的视图。我目前正在研究如何使用基于类的视图来执行此操作。

def product_list(request):
f = ProductFilter(request.GET, queryset=Product.objects.all())
return render_to_response('my_app/template.html', {'filter': f})

3 个答案:

答案 0 :(得分:7)

更多的挖掘,我设法回答它。我使用了这里的代码https://github.com/rasca/django-enhanced-cbv

我将list.py的内容添加到我的主应用中main_app/filter_mixin.py

然后在应用程序中我向列表视图添加了一个搜索,我添加了这样的文件filter.py(与文档相同)

from django_filters import FilterSet
from .models import Contact


class ContactFilter(FilterSet):
    class Meta:
        model = Contact
        fields = ['name_first', 'name_last']

现在view.py变为:

from vanilla import ListView

from .filter import ContactFilter
from galleria.filter_mixin import ListFilteredMixin


class ContactList(ListFilteredMixin, ListView):
    filter_set = ContactFilter

答案 1 :(得分:1)

这是一个仅覆盖查询集以允许过滤和上下文将过滤器嵌入模板的示例。

class ObjFilter(django_filters.FilterSet):
    class Meta:
        model = Obj
        fields = ["field1", "field2"]


class ObjView(ListView):
    template_name = "template.html"
    model = Obj
    paginate_by = 10
    ordering = ["-id"]

    def get_queryset(self):
        queryset = super().get_queryset()
        filter = ObjFilter(self.request.GET, queryset)
        return filter.qs

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        queryset = self.get_queryset()
        filter = ObjFilter(self.request.GET, queryset)
        context["filter"] = filter
        return context

答案 2 :(得分:0)

如链接Viewing subsets of objects

中所述

您可以使用类似views.py

class modelListView(someGenericView): queryset = modelName.object.filter(myFilter)