我像这样克隆我的mainSection（我必须克隆它，因为在AJAX上添加了#main的新元素，我不想搜索它们）：
$mainSection = $('#main').clone(true);
然后我在克隆的主要部分中搜索元素：
var searchTermHtml = 'test';
$foundElement = $mainSection.filter(":contains('"+searchTermHtml+"')");
当我找到字符串＆＃39; test＆＃39;在#mainSection中我想从$ mainSection中获取原始元素，所以我可以通过以下方式滚动到它：
var stop = $foundElementOriginal.offset().top;
window.scrollTo(0, stop);
问题是：我如何获得$ foundElementOriginal？
答案 0 :(得分：2)
由于您在克隆它之后更改了#main的内容，因此使用结构化内容（子元素在其父元素中等）将不可靠。
在克隆它之前，您需要在#main 中的元素上添加某种标记，以便稍后可以使用这些标记来关联您找到的克隆元素到#main中的原始元素。您可以通过向其添加data-*属性来标记所有元素，但是如果您对实际问题域有了更多的了解，我希望您可以避免那么挥霍。
以下是一个完整的示例：Live Copy
<!DOCTYPE html>
<html>
<head>
<script src="http://code.jquery.com/jquery-1.11.0.min.js"></script>
<meta charset="utf-8">
<title>Example</title>
</head>
<body>
<div id="main">
<p>This is the main section</p>
<p>It has three paragraphs in it</p>
<p>We'll find the one with the number word in the previous paragraph after cloning and highlight that paragraph.</p>
</div>
<script>
(function() {
"use strict";
// Mark all elements within `#main` -- again, this may be
// overkill, better knowledge of the problem domain should
// let you narrow this down
$("#main *").each(function(index) {
this.setAttribute("data-original-position", String(index));
});
// Clone it -- be sure not to append this to the DOM
// anywhere, since it still has the `id` on it (and
// `id` values have to be unique within the DOM)
var $mainSection = $("#main").clone(true);
// Now add something to the real main
$("#main").prepend("<p>I'm a new first paragraph, I also have the word 'three' but I won't be found</p>");
// Find the paragraph with "three" in it, get its original
// position
var originalPos = $mainSection.find("*:contains(three)").attr("data-original-position");
// Now highlight it in the real #main
$("#main *[data-original-position=" + originalPos + "]").css("background-color", "yellow");
})();
</script>
</body>
</html>