Question

所以我试图制作一个基本的游戏，有人可以进入头部或尾部，然后将该值转换为数字，然后给出答案，好像它是对的。那么如何将头转换为1并将尾部转换为0

       public static void main(String[]args){
    int coin = (int)(Math.random() * 2+1);
    Scanner input = new Scanner(System.in);
    System.out.print("Do you think the coin will be heads or tail");
    String guess = input.next();
    if (guess != "heads" || guess !="tails")
    System.out.println(" please enter a heads or tails");
    System.out.print("Do you think the coin will be heads or tail");
     if (guess == "heads")
      int guess = 1;
     else if(guess == "tails")
         int guess = 0 ;
     else
         System.out.println(" please enter a heads or tails");
     if (guess == coin)
           System.out.println("Got it");
    else if (coin == 0)
      System.out.println("Sorry, it is a head");
    else
      System.out.println("Sorry, it is a tail");

             }

Answer 1

那么如何将磁头转换为1并将尾部转换为0？

    int guessValue = 0;
    if (guess.equals("heads")) {
        guessValue = 1;
    }

Answer 2

你不会想要＆＃34;转换＆＃34;将值转换为数字。您应该使用单独的变量来保存整数值。我想你也希望这是＆＃34;连续＆＃34;，在这种情况下，你想要一个while循环来继续获取值：

while(true){
    int coin = (int)(Math.random() * 2+1);
    System.out.print("Do you think the coin will be heads or tail");
    String guess = input.nextLine(); // nextLine should work fine

    while(!guess.equals("heads") && !guess.equals("tails")){ // loop until you get a correct input
        System.out.println(" please enter a heads or tails");
        guess = input.nextLine();
    }

    int choice = 0;
    if (guess.equals("tails")) // use .equals(yourString) to compare values of strings
       choice = 1; // only change to 1 if it's tails, otherwise it's heads
    if (choice == coin)
       System.out.println("Got it!");
    else if (coin == 0)
        System.out.println("Sorry, it is a head");
    else
        System.out.println("Sorry, it is a tail");
}

您还可以检查输入是否要再次播放，然后使用break声明，如果他们表示他们没有。

猜测头或尾 - 将字符串转换为if语句中的int

2 个答案: