我有一个包含简单搜索表单的GWTP PresenterWidget
和View
对。
目前我通过调用SubmitHandler
的{{1}}方法将getSearchForm()
添加到表单中,这是不好的做法,因为它引用了实际的类而不是接口:
View
有没有办法在public class HeaderPresenter extends PresenterWidget<HeaderPresenter.MyView>
{
public interface MyView extends View
{
void submitForm();
Form getSearchForm();
}
// ...omitted for brevity
@Inject
public HeaderPresenter(EventBus eventBus, DispatchAsync dispatchAsync, MyView view, PlaceManager placeManager)
{
// ...omitted for brevity
}
@Override
protected void onBind()
{
super.onBind();
getView().getSearchForm().addSubmitHandler(new SubmitHandler()
{
@Override
public void onSubmit(SubmitEvent event)
{
// stops the form submission
event.cancel();
// now we can do our stuff
String query = getView().getSearchQuery();
if(query != "") // don't search for a blank string
{
PlaceRequest request = new PlaceRequest.Builder().nameToken(NameTokens.search).with("q", query).build();
placeManager.revealPlace(request);
}
}
});
}
中添加SubmitHandler
,还是我必须将该代码放入HeaderPresenter
?
我希望在Presenter中保留尽可能多的逻辑。
答案 0 :(得分:1)
我在这里找到了对此的讨论,并最终使用了Thomas Broyer建议的选项4:
https://groups.google.com/forum/#!topic/google-web-toolkit/Fbo-SEDjRa4