我有主片段,我想将ArrayList
传递给Activity
类,我会在ListView中显示结果。
片段类:
public class StudentActivity extends Fragment implements OnClickListener {
}
我有数据
ArrayList<> allStudents = new ArrayList();
allStudents.add(new Student("H", 99, 93) );
allStudents.add(new Student("C", 98, 92) );
allStudents.add(new Student("B", 98, 91) );
allStudents.add(new Student("A", 80, 94) );
allStudents.add(new Student("F", 70, 84) );
现在我想发送&#34;所有学生&#34;对象到新的活动类StudentResult();
我在片段类中使用:
Intent intent = new Intent(getActivity(), StudentResult.class);
intent.putExtra("ExtraData", allStudents);
startActivity(intent);
并在目标类中显示ListView();
中的对象public class ResultActivity extends Activity {
public void myData(ArrayList<allStudents> myArray) {
marjslistview = (ListView) findViewById(R.id.listView1);
arrayAdapter = new ArrayAdapter<allStudents>(this, R.layout.student_list, myArray);
...
ScoreLV.setAdapter(arrayAdapter);
...
}
}
提前感谢!
答案 0 :(得分:5)
在片段中创建自定义界面:
public interface OnFragmentInteractionListener {
public void onFragmentSetStudents(ArrayList<Student>);
}
在您的活动中实施此界面:
public class YourActivity extends Activity implements YourFragment.OnFragmentInteractionListener {
private ArrayList<Student> allStudents;
}
现在你必须覆盖声明的方法(在Activity
中):
@Override
public void onFragmentSetStudents(ArrayList<Student> students) {
allStudents = students;
}
然后你只需要在片段中使用监听器启动此方法:
OnFragmetInteractionListener listener = (OnFragmentInteractionListener) activity;
listener.onFragmentStudents(allStudents)
答案 1 :(得分:1)
在Activity
:
Bundle bundle = getIntent().getExtras();
ArrayList allStudents = bundle.get("ExtraData");
我认为您需要将ArrayAdapter
定义为:
arrayAdapter = new ArrayAdapter<Student>(this, R.layout.student_list, allStudents);
你有其余的代码,只需添加上面的代码。它应该工作。