Question

我真的试着不在这里问这个问题，但经过几个小时的努力，我被困住了。所以这里...希望我能清楚。

我想要的输出是：

({
    following = "";
    followingMe = "";
},{
    following = "";
    followingMe = "";
},{...})

进入的数据看起来像这样，我想要做的就是排序

({
    user = "me";
    following = "sam";
},{
    user = "sam";
    following = "me";
},{
    user = "foo";
    following = "me";
},{
    user = "me";
    following = "bar";
},...)

我想组织它，如果我跟随＆＃34; sam＆＃34;而且他跟着我，这是一本字典。如果＆＃34; foo＆＃34;跟着我，然后following="(null)＆＃34;和followingMe="sam" ......等等。这就是为什么我不想问这个问题......很难解释。

这里是我的代码，但它只是给我一遍又一遍的条目......那是什么错字？

NSMutableDictionary *temp = [NSMutableDictionary new];
int i = 0;
while (i < array.count) {
    [temp removeAllObjects];
    if ([[[array objectAtIndex:i]valueForKey:@"user"]isEqualToString:_user]){
    //means I'm following this person
        [temp setValue:[[array objectAtIndex:i] valueForKey:@"following"] forKey:@"following"];

        if ([[_allfriends valueForKey:@"followingMe"]containsObject:[[array objectAtIndex:i] valueForKey:@"following"]]) {
        //check to see if this person is already following me

            [[_allfriends objectAtIndex:[[_allfriends valueForKey:@"followingMe"] indexOfObject:
            [[array objectAtIndex:i] valueForKey:@"following"]]] setObject:[[array objectAtIndex:i] valueForKey:@"following"] forKey:@"following"];
            //trying to update at the index where this person is following me

        }else{
            [temp setObject:@"(null)" forKey:@"followingMe"];
            [_allfriends addObject:temp];
        }
    }else{
        //this person is following me
        [temp setObject:[[array objectAtIndex:i]valueForKey:@"user"] forKey:@"followingMe"];

        if ([[_allfriends valueForKey:@"following"]containsObject:[[array objectAtIndex:i] valueForKey:@"user"]]) {
        //check to see if I'm following this pseron

            [[_allfriends objectAtIndex:[[_allfriends valueForKey:@"following"] indexOfObject:
            [[array objectAtIndex:i] valueForKey:@"user"]]] setObject:[[array objectAtIndex:i] valueForKey:@"user"] forKey:@"followingMe"];
            //try to update followingMe at that index

        }else{
            [temp setObject:@"(null)" forKey:@"following"];
            [_allfriends addObject:temp];
        }
    }
    i++;
}

所以我的逻辑是检查我的姓名（user或following）。然后我会检查此人是否已经followingMe。它是_allfriends中的一个条目，我需要获取该索引，我想更新＆＃34; following＆＃34; ...有意义吗？我在这里做错了什么？

Answer 1

U可以使用Set

对数组进行排序

SortedArr = [NSMutableArray arrayWithArray:[[NSSet setWithArray: UnsortedArr] allObjects]];

Answer 2

显然问题出在NSMutableDictionary *temp = [NSMutableDictionary new];上。我不确定this post是否适用，但它让我重写了我的代码。临时值附加到_allfriends数组，因此当临时更改时，_allfriends中的所有内容都会更改。我的循环逻辑是正确的，但我重写了这样：

NSString *key = [NSString new];
for (int i = 0; i < array.count; i++) {
    if ([[[array objectAtIndex:i]valueForKey:@"user"]isEqualToString:_user]){
        key = [[array objectAtIndex:i] valueForKey:@"following"];
        if ([[_allfriends valueForKey:@"followingMe"]containsObject:key]) {
            [_allfriends removeObjectAtIndex:[[_allfriends valueForKey:@"followingMe"] indexOfObject:key]];
            [_allfriends insertObject:[NSDictionary dictionaryWithObjectsAndKeys:key, @"following", key, @"followingMe", nil] atIndex:_allfriends.count];
        }else{
            [_allfriends insertObject:[NSDictionary dictionaryWithObjectsAndKeys:key, @"following", @"(null)", @"followingMe", nil] atIndex:_allfriends.count];
        }
    }else{
        key = [[array objectAtIndex:i] valueForKey:@"user"];
        if ([[_allfriends valueForKey:@"following"]containsObject:key]) {
            [_allfriends removeObjectAtIndex:[[_allfriends valueForKey:@"following"] indexOfObject:key]];
            [_allfriends insertObject:[NSDictionary dictionaryWithObjectsAndKeys:key, @"following", key, @"followingMe", nil] atIndex:_allfriends.count];
        }else{
            [_allfriends insertObject:[NSDictionary dictionaryWithObjectsAndKeys:key, @"followingMe", @"(null)", @"following", nil] atIndex:_allfriends.count];
        }
    }
}

希望有人帮助......

从以前的字典数组中创建和排序字典数组

2 个答案: