Question

我有这段代码：

public ref class NativeDll
{
    DllInterface *dllInterface;
public:
    NativeDll(String ^dllName)
    {
        msclr::interop::marshal_context context;
        std::string stdDllName = context.marshal_as<std::string>(dllName);

        dllInterface=new DllInterface(stdDllName);
    }
    NativeDll()
    {
        auto assembly= Assembly::GetExecutingAssembly();
        String ^path=Path::GetDirectoryName(assembly->FullName);
        auto pathName=Path::Combine(path,"MyDLL.dll");
        NativeDll(pathName);
    }
};

当我编译它时，我得到错误：

'pathName' : redefinition; different type modifiers

它在线生成此错误：

  NativeDll(pathName);

将路径名更改为任何内容都会产生相同的错误。为什么我收到此错误？

Answer 1

在C ++中，您无法从另一个构造函数中调用构造函数。也不是在C ++ / Cli AFAIK中。创建一个两个构造函数都调用的方法：

NativeDll(String ^dllName)
{
    initialize(dllName);
}

NativeDll()
{
    auto assembly= Assembly::GetExecutingAssembly();
    String ^path=Path::GetDirectoryName(assembly->FullName);
    auto pathName=Path::Combine(path,"MyDLL.dll");

    initialize(dllName);
}

void initialize(String ^dllName)
{
    msclr::interop::marshal_context context;
    std::string stdDllName = context.marshal_as<std::string>(dllName);

    dllInterface=new DllInterface(stdDllName);
}

为什么我在c ++ / clr中收到此编译错误

1 个答案: