Question

我正在使用MyPhpAdmin 4.2可视化编辑器。当我调用存储过程并传递参数值时，我没有返回任何行，并输出参数值显示空值。

SET @p0='1'; SET @p1='1'; SET @p2='41'; SET @p3='1'; CALL `ps_stp_getPrograms`(@p0, @p1, @p2, @p3);

BEGIN 
  CREATE TEMPORARY TABLE temp_progs(prog_id bigint(20));
  IF @countyID > 0 THEN                    
    INSERT INTO temp_progs (prog_id)
    SELECT 1 from ps_prog_county 
    WHERE ps_prog_county.county_id = @countyID AND ps_prog_county.prog_id = @progID;                  
  END IF;  
  IF @ServiceID > 0 THEN 
    INSERT INTO temp_progs (prog_id)
    SELECT 1 from ps_prog_services 
    WHERE ps_prog_services.svc_id = @ServiceID AND ps_prog_services.prog_id = @progID;
  END IF; 
  IF @popID > 0 THEN   
    INSERT INTO temp_progs (prog_id)
    SELECT 1 from ps_prog_served
    WHERE ps_prog_served.served_id = @popID AND ps_prog_served.prog_id = @progID;
  END IF; 
SELECT DISTINCT prog_id FROM temp_progs;
SELECT @progID, @countyID, @ServiceID, @popID;
END

如果我设置了它按预期返回的值

SET @progID = 1;
SET @countyID = 1;
SET @ServiceID = 41;
SET @popID = 1;

Answer 1

您必须在其正文中使用相同的存储过程参数名称。

使用用户变量时，它们与参数中的SP不同。

示例：

delimiter //
create procedure 
  ps_stp_getPrograms(
    IN progID int
    , IN countyID int
    , IN ServiceID int
    , IN popID int
  )
BEGIN 
  CREATE TEMPORARY TABLE temp_progs( prog_id bigint(20) );
  IF countyID > 0 THEN                    
    INSERT INTO temp_progs( prog_id )
      SELECT 1 from ps_prog_county 
       WHERE ps_prog_county.county_id = countyID 
         AND ps_prog_county.prog_id = progID;                  
  END IF;  
  IF ServiceID > 0 THEN 
    INSERT INTO temp_progs ( prog_id )
      SELECT 1 from ps_prog_services 
       WHERE ps_prog_services.svc_id = ServiceID 
         AND ps_prog_services.prog_id = progID;
  END IF; 
  IF popID > 0 THEN   
    INSERT INTO temp_progs ( prog_id )
      SELECT 1 from ps_prog_served
       WHERE ps_prog_served.served_id = popID 
         AND ps_prog_served.prog_id = progID;
  END IF; 

  SELECT DISTINCT prog_id FROM temp_progs;
  SELECT progID, countyID, ServiceID, popID;

END; 
//
delimiter ;

MySQL存储过程不返回结果，IN参数返回NULL

1 个答案: