Question

是否有更快的方法来执行以下查询？

我需要根据同一张表中另一列pod.podId的分钟找到DueDate。

DECLARE @sodi = 7 -- this is the function parameter

select top 1 
    pod.podId
from 
    sod 
inner join 
    idt on sod.ItemID = idt .ItemID
inner join 
    pod on pod.ProductID = idt.ProductID and pod.DueDate is not null and (pod.OrderQty >= pod.ReceivedQty)
inner join 
    poh on poh.poID = pod.poId and poh.StatusID <>32
where 
    sod.soid = @sodi
    and pod.DueDate = (select min (pod.DueDate)
                       from sod 
                       inner join idt on sod.ItemID = id.ItemID
                       inner join pod on pod.ProductID = id.ProductID and pod.DueDate is not null and (pod.OrderQty >= pod.ReceivedQty)
                       inner join poh on poh.poID = pod.poId and poh.StatusID <> 32
                       where sod.sodID = @sodi)

Answer 1

您可以在Order By

上执行pod.DueDate

DECLARE @sodi = 7 -- this is the function parameter

select top 1 
    pod.podId
from 
    sod 
inner join 
    idt on sod.ItemID = idt .ItemID
inner join 
    pod on pod.ProductID = idt.ProductID and pod.DueDate is not null and (pod.OrderQty >= pod.ReceivedQty)
inner join 
    poh on poh.poID = pod.poId and poh.StatusID <>32
where 
    sod.soid = @sodi
order by pod.DueDate

Answer 2

select top 1 pod.podId
 from sod 
 join idt 
   on sod.ItemID = idt .ItemID 
  and sod.soid = @sodi
 join pod 
   on pod.ProductID = idt.ProductID 
  and pod.DueDate is not null 
  and (pod.OrderQty >= pod.ReceivedQty)     
 join poh on poh.poID = pod.poId 
  and poh.StatusID <> 32
order by pod.DueDate, pod.podId

我将条件移动到连接中，查询优化器变得更聪明

使用最少的另一列检索列的更快方法是什么？

2 个答案: