MySQL SET Query中的引用字段

Question

所以我有一张看起来像这样的表

+----+----------------------+--------------------------+----------+----------+
| id | fullname             | email                    | username | password |
+----+----------------------+--------------------------+----------+----------+
|  1 | John Doe             | johndoe@example.com      | johndoe  | password |
|  2 | Jane Doe             | janedoe@example.com      | janedoe  | password | 
+----+----------------------+--------------------------+----------+----------+

我想要做的是将“密码”更改为“1”。例如，在该查询之后，表格看起来像这样：

+----+----------------------+--------------------------+----------+----------+
| id | fullname             | email                    | username | password |
+----+----------------------+--------------------------+----------+----------+
|  1 | John Doe             | johndoe@example.com      | johndoe  | johndoe1 |
|  2 | Jane Doe             | janedoe@example.com      | janedoe  | janedoe1 | 
+----+----------------------+--------------------------+----------+----------+

我尝试UPDATE table SET password=username+"1" WHERE id=1;，但这不起作用。这并不奇怪。

我该怎么做？

Answer 1

使用concat

UPDATE table SET password=CONCAT(username,'1') ;

Demo