Question

我在这里看到了一些关于同一类问题的主题，但是我还没有想出一个解决方案，因此对提出类似问题表示歉意。

我正在尝试接收来自数据库的所有数据并回显到将显示所有结果的页面。

继承我的代码：

<?php

$event = mysql_query("SELECT * FROM `events`");
while($get_event = mysql_fetch_array($event)) {
    $event_title        = $get_event['title'];
    $event_disc         = nl2br($get_event['discription']);
    $event_date         = $get_event['event_date'];
    $event_time         = $get_event['event_time'];
    $event_contname     = $get_event['contact_name'];
    $event_contnum      = $get_event['contact_num'];
    $event_username     = $get_event['username'];
    $event_number1      = $get_event['number1'];
    $event_line2        = $get_event['line2'];
    $event_city         = $get_event['city'];
    $event_postcode     = $get_event['postcode'];
    $event_country      = $get_event['country'];

}
echo '
<div class="col-md-6">
    <div class="funny-boxes funny-boxes-left-green">
        <div class="row">
            <div class="col-md-4 funny-boxes-img">
                <img alt="" src="' . $user_data['profile'] . '" style="width: 135px; height: 135px;" class="img-responsive">
                <ul class="list-unstyled">
                   <li><u>Contact Name:</u> <br>' . $event_contname . '</li>
                   <li><u>Num / Email:</u> <br>' . $event_contnum . '</li>
                   <li><u>Address:</u> <br>' . $event_number1 . ' <br> ' . $event_line2 . ' <br> ' . $event_city . ' <br> ' . $event_postcode . ' <br> ' . $event_country . ' </li>
                   <li><u>Date:</u> ' . $event_date .'</li>
                   <li><u>Time:</u> ' . $event_time .'</li>
                </ul>
            </div>
            <div class="col-md-8">
                <h2>Destony Conferance 2014</h2>
                <p>' . $event_disc .'</p>
            </div>
        </div>                            
    </div>                    
</div>';

?>

Answer 1

您需要将echo语句放在循环中。否则它只显示循环的最后一次迭代的结果：

while($get_event = mysql_fetch_array($event)) {
    $event_title        = $get_event['title'];
    $event_disc         = nl2br($get_event['discription']);
    $event_date         = $get_event['event_date'];
    $event_time         = $get_event['event_time'];
    $event_contname     = $get_event['contact_name'];
    $event_contnum      = $get_event['contact_num'];
    $event_username     = $get_event['username'];
    $event_number1      = $get_event['number1'];
    $event_line2        = $get_event['line2'];
    $event_city         = $get_event['city'];
    $event_postcode     = $get_event['postcode'];
    $event_country      = $get_event['country'];
    echo '
    <div class="col-md-6">
        <div class="funny-boxes funny-boxes-left-green">
            <div class="row">
                <div class="col-md-4 funny-boxes-img">
                    <img alt="" src="' . $user_data['profile'] . '" style="width: 135px; height: 135px;" class="img-responsive">
                    <ul class="list-unstyled">
                       <li><u>Contact Name:</u> <br>' . $event_contname . '</li>
                       <li><u>Num / Email:</u> <br>' . $event_contnum . '</li>
                       <li><u>Address:</u> <br>' . $event_number1 . ' <br> ' . $event_line2 . ' <br> ' . $event_city . ' <br> ' . $event_postcode . ' <br> ' . $event_country . ' </li>
                       <li><u>Date:</u> ' . $event_date .'</li>
                       <li><u>Time:</u> ' . $event_time .'</li>
                    </ul>
                </div>
                <div class="col-md-8">
                    <h2>Destony Conferance 2014</h2>
                    <p>' . $event_disc .'</p>
                </div>
            </div>                            
        </div>                    
    </div>';
}

MySql / PHP只从数据库返回一个结果

1 个答案: