Question

我正在处理从数据库中提取数据的页面。捕获PHP time()并将其与用户内容一起保存到数据库中。

我想要使用JavaScript从当前时间减去capturedTime并显示帖子在hr : min : s中的显示时间，并且应该是有效的。

HTML：

<div class = 'responses'>
   <p class = 'capturedTime' style='display: none;'>123456789</p>
</div>

jQuery的：

$(document).on('click', '.responses', function () {
     $this = $( this );
     timeC = $this.prev('.capturedTime').text();
     timeNow = $.now()
     timeLapsed = ( timeNow - timeC )/1000;
     seconds = timeLapsed/60;
     mins = seconds/60;
     hrs = mins/24;
     if ( timeLapsed !== NaN ){
         alert(seconds + '------' + mins + '---' + hrs);
     }
 });

Answer 1

我建议您以这种方式更改代码：

Fiddle

<body>
    <div class='responses'>
        <p class='capturedTime' data="1401270715145"></p>
    </div>
</body>






var $times, timer;

$times = $('.capturedTime');
timer = setInterval(function () {
    var i, len, cache, value, now, minutes, seconds;

    for (i = 0, len = $times.length; i < len; i = i + 1) {
        cache = $times.eq(i);
        now = new Date().getTime();
        value = new Date(now - parseInt(cache.attr("data")));
        minutes = value.getMinutes();
        seconds = value.getSeconds();
        cache.html("m:" + minutes + " ss:" + seconds);
    }

}, 1000);

Answer 2

试试这个：

<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script src="http://timeago.yarp.com/jquery.timeago.js" type="text/javascript"></script>

<script type="text/javascript">
    $(function(){
        var lastUpdate = new Date($(".capturedTime").html()*1000)
        alert($.timeago(lastUpdate));
         });                
</script>

或访问此page

使用PHP时间计算JavaScript时间

2 个答案: