查询没有返回任何结果，这是字符串格式问题吗？

Question

使用parse.com和JavaScript。

以下代码应该使我能够针对parse.com数据库查询用户输入的字符串并返回结果。我知道有结果存在，但似乎字符串没有以正确解释的格式捕获？

****使用JavaScript的Parse.com查询应该搜索班级＆＃34; myBadges＆＃34;和＆＃34; das＆＃34;字符串＆＃34; friendName **

的列

var myBadgeUploader = Parse.Object.extend("myBadges");

function friendFeed() {

    var query = new Parse.Query(myBadgeUploader);
    query.startsWith("das", friendName);
    query.find({
        success: function(results) {
          console.log(results);
           }
    });
}

---

****代码应该捕获＆＃34; FriendName＆＃34;在查询中使用的字符串**

$(document).ready(function() {  
    $(document).on('click','.username', function (event) {
        event.preventDefault();
        friendName = $(this).text();
        console.log(friendName);
        friendFeed();
    });
});

用于创建用户列表和要点击的用户名的代码。

var currentUser = Parse.User.current();  
var FriendRequest = Parse.Object.extend("FriendRequest");

var query = new Parse.Query(FriendRequest);
query.include('toUser');
// query.include('fromUser');
//query.include('pic');
query.equalTo("fromUser", currentUser);
query.equalTo("status", "Request sent");

query.find({
    success: function(results) {
        // If the query is successful, store each image URL in an array of image URL's
        imageURLs = [];
        Username = [];
        for (var i = 0; i < results.length; i++) { 
            var object = results[i].get("toUser");
            imageURLs.push(object.get("pic"));
            Username.push(object.get("username"));
        }


        // If the imageURLs array has items in it, set the src of an IMG element to the first URL in the array
        console.log(imageURLs);
        console.log(Username);
        for(var j = 0; j < imageURLs.length; j++) {  
            $('#container').append("<img class='images' src='" + imageURLs[j] + "'/>");
            $('#container').append("<div class='username'>'"+Username[j]+"'</div>"); }

    },
    error: function(error) {
        // If the query is unsuccessful, report any errors
        alert("Error: " + error.code + " " + error.message);
    }

});