Question

好的，所以我在这里得到了一个Quartz（2.2.1版）作业，该作业应该实例化另外两个作业，为每个作业创建并添加两个触发器，并将两个作业添加到调度程序中，在之后删除它们设置通过JobDataMap传入的间隔。

当调度程序运行此作业时，它会抛出以下异常：

org.quartz.JobPersistenceException: The job (DEFAULT.countdown15, countdownGroup) referenced by the trigger does not exist.

在第71行抛出异常：

sched.scheduleJob(countdown15Trigger2);

我无法弄清楚为什么这个工作在那时不存在，因为它应该是由早期的newJob调用创建的，并且由第70行添加到调度程序中：

sched.scheduleJob(countdown15, countdown15Trigger1);

所以，我暂时注释掉那一行并试图再次运行程序，于是我在第72行得到了这个例外：

第72行：

sched.scheduleJob(countdown60, countdown60Trigger1);

异常：

org.quartz.SchedulerException: Trigger does not reference given job!

好的，所以现在我有两个scheduleJob调用抛出两个不同的异常，尽管我可以告诉我按照正确的语法。但是第一个scheduleJob调用必须正常工作，因为异常发生在代码的后面，所以现在我将注释掉所有其他scheduleJob调用，看看会发生什么。

然后我在第70行得到了这个错误，第一个也是现在只有scheduleJob调用：

org.quartz.ObjectAlreadyExistsException: Unable to store Job : 'countdownGroup.countdown15', because one already exists with this identification.

我真的不知道从哪里开始，所以这里是顶级工作的完整代码。有什么想法吗？

public class ShowClockJob implements Job {

public ShowClockJob() {}

@Override
public void execute(JobExecutionContext context)
    throws JobExecutionException {
    JobDataMap dm = context.getJobDetail().getJobDataMap();
    int min = dm.getInt("min");  //show's runtime in minutes
    int ms = min * 60000;  //convert the runtime in minutes to millisec
    Scheduler sched = context.getScheduler();
    JobDetail countdown15 = newJob(CountdownJob15.class)
            .withIdentity(jobKey("countdown15", "countdownGroup"))
            .build();

    JobDetail countdown60 = newJob(CountdownJob60.class)
            .withIdentity("countdown60", "countdownGroup")
            .build();

    Trigger countdown15Trigger1 = newTrigger()
            .withIdentity("countdown15Trigger1", "countdownGroup")
            .withSchedule(cronSchedule("45 5 * * * ?")
                .withMisfireHandlingInstructionDoNothing())
            .forJob(jobKey("countdown15", "countdownGroup"))
            .build();

    Trigger countdown15Trigger2 = newTrigger()
            .withIdentity("countdown15Trigger2", "countdownGroup")
            .withSchedule(cronSchedule("55 19,32,46 * * * ?")
                .withMisfireHandlingInstructionDoNothing())
            .forJob(jobKey("countdown15, countdownGroup"))
            .build();

    Trigger countdown60Trigger1 = newTrigger()
            .withIdentity("countdown60Trigger1", "countdownGroup")
            .withSchedule(cronSchedule("0 17,29,44 * * * ?")
                .withMisfireHandlingInstructionDoNothing())
            .forJob(jobKey("countdown60, countdownGroup"))
            .build();

    Trigger countdown60Trigger2 = newTrigger()
            .withIdentity("countdown60Trigger2", "countdownGroup")
            .withSchedule(cronSchedule("50 57 * * * ?")
                .withMisfireHandlingInstructionDoNothing())
            .forJob("countdown60, countdownGroup")
            .build();
    try {
        sched.scheduleJob(countdown15, countdown15Trigger1);
        sched.scheduleJob(countdown15Trigger2);
        sched.scheduleJob(countdown60, countdown60Trigger1);
        sched.scheduleJob(countdown60Trigger2);

        Thread.sleep(ms);  //sleep for the length of the showtime, 

        //...then shut down the countdown jobs
        sched.deleteJob(jobKey("countdown15","countdownGroup"));
        sched.deleteJob(jobKey("countdown60","countdownGroup"));
    } catch (SchedulerException | InterruptedException ex) {
        Logger.getLogger(ShowClockJob.class.getName()).log(Level.SEVERE, null, ex);
    }

}

}

Answer 1

原来这是一个简单的语法错误。在除了第一个触发器创建块之外的所有块中，在forJob方法中，我省略了将jobKey和jobGroup分成两个字符串的中间两个括号。

所以这个：

forJob("countdown60, countdownGroup");

应该是这样的：

forJob("countdown60", "countdownGroup");

Quartz scheduleJob Exceptions

1 个答案: