我有一个哈希数组,为了论证起见,这样:
[{"foo"=>"1", "bar"=>"1"}, {"foo"=>"2", "bar"=>"2"}]
使用Rspec,我想测试数组中是否存在"foo" => "2"
,但我不在乎它是第一项还是第二项。我试过了:
[{"foo" => "1", "bar" => "2"}, {"foo" => "2", "bar" => "2"}].should include("foo" => "2"))
但这并不起作用,因为哈希应该完全匹配。有没有办法部分测试每个哈希的内容?
答案 0 :(得分:29)
怎么样?
hashes = [{"foo" => "1", "bar" => "2"}, {"foo" => "2", "bar" => "2"}]
expect(hashes).to include(include('foo' => '2'))
答案 1 :(得分:7)
您可以使用any?
方法。有关文档,请参阅this。
hashes = [{"foo" => "1", "bar" => "2"}, {"foo" => "2", "bar" => "2"}]
expect(hashes.any? { |hash| hash['foo'] == '2' }).to be_true
答案 2 :(得分:2)
您可以使用可组合匹配器
http://rspec.info/blog/2014/01/new-in-rspec-3-composable-matchers/
但我更喜欢定义像这样的自定义匹配器
require 'rspec/expectations'
RSpec::Matchers.define :include_hash_matching do |expected|
match do |array_of_hashes|
array_of_hashes.any? { |element| element.slice(*expected.keys) == expected }
end
end
并在像这样的规范中使用它
describe RSpec::Matchers do
describe '#include_hash_matching' do
subject(:array_of_hashes) do
[
{
'foo' => '1',
'bar' => '2'
}, {
'foo' => '2',
'bar' => '2'
}
]
end
it { is_expected.to include_hash_matching('foo' => '1') }
it { is_expected.to include_hash_matching('foo' => '2') }
it { is_expected.to include_hash_matching('bar' => '2') }
it { is_expected.not_to include_hash_matching('bar' => '1') }
it { is_expected.to include_hash_matching('foo' => '1', 'bar' => '2') }
it { is_expected.not_to include_hash_matching('foo' => '1', 'bar' => '1') }
it 'ignores the order of the keys' do
is_expected.to include_hash_matching('bar' => '2', 'foo' => '1')
end
end
end
Finished in 0.05894 seconds
7 examples, 0 failures
答案 3 :(得分:2)
hashes = [{"foo" => "1", "bar" => "2"}, {"foo" => "2", "bar" => "2"}]
expect(hashes).to match([a_hash_including('foo' => '2'), a_hash_including('foo' => '1')])
答案 4 :(得分:0)
如果哈希的单独测试不是严格的要求,我会这样做:
[{"foo" => "1", "bar" => "2"}, {"foo" => "2", "bar" => "2"}].map{ |d| d["foo"] }.should include("2")