Question

(defun next ()
  (defparameter *sentences*
    '(
      (1 . "Test 1")
      (2 . "Test 2")))

  (let (sentence '(assoc 2 *sentences*)) ;This quote is needed, another program evaluates this.
    (format t "*sentences*:~%~a~%sentence: ~a~%" *sentences* sentence)))

它提供输出＆＃34; *句子*：（（1。测试1）（2。测试2））句子：NIL＆＃34;。

为什么它不给（2。测试2）作为＆＃34;句子＆＃34;的价值？

提前致谢。

编辑：添加括号。原始程序与括号匹配。

Answer 1

您的let表格中缺少括号：

(defun next ()
  (defparameter *sentences*
    '(
      (1 . "Test 1")
      (2 . "Test 2")))
  (let ((sentence (assoc 2 *sentences*))) ;no quote, just parentheses ;-)
    (format t "*sentences*:~%~a~%sentence: ~a~%" *sentences* sentence)))

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