退出特殊按钮

Question

我创建了一个自定义退出按钮，如果按下该按钮，我希望代码终止。我怎样才能做到这一点？

String[] button1 = {"exit", "next"};
//if next is pressed
if (code == JOptionPane.YES_OPTION) {
  JOptionPane.showMessageDialog(
              null, 
              "Knock knock" + "\nWho is there",
              "The Jasmin Project",
              JOptionPane.YES_NO_OPTION);
  int no = JOptionPane.showOptionDialog(null, "Want to view more?",
              "The Jasmin Project",
              JOptionPane.YES_NO_OPTION,
              JOptionPane.INFORMATION_MESSAGE,
              null,
              button1,
              button1[0]);
  //end code if exit is pressed            
  if (no == JOptionPane.NO_OPTION) {
     System.exit(1);
  }
}

Answer 1

您的错误就在这一行：

String[] button1 = {"exit", "next"};

试试这个：

String[] button1 = {"next", "exit"};

第一个选项是是，第二个选项是否。