Question

我试图通过最新更新日期时间来查询查询，该日期时间大于现在上升然后小于现在下降。这是我想要的输出：

2014-06-01 00:00:00
2014-06-04 00:00:00
2014-06-05 00:00:00
2014-06-06 00:00:00
2014-05-19 00:00:00
2014-05-15 00:00:00
0000-00-00 00:00:00

但是我得到了这个：

2014-06-01 00:00:00
2014-06-04 00:00:00
2014-06-05 00:00:00
2014-06-06 00:00:00
0000-00-00 00:00:00
2014-05-15 00:00:00
2014-05-19 00:00:00

我使用的查询是：

SELECT lastupdated FROM users ORDER BY lastupdated > NOW() DESC, lastupdated ASC;

Answer 1

您可以使用UNION：

执行此操作

SELECT lastupdated 
FROM users 
WHERE lastupdated > NOW()
ORDER BY lastupdated  DESC

UNION

SELECT lastupdated 
FROM users 
WHERE lastupdated <= NOW()
ORDER BY lastupdated ASC;

Answer 2

有什么问题？日期0000-00-00已过去，因此该列表首先列出。如果你想要它总体上，请明确地把它放在那里：

order by (case when lastupdated = '0000-00-00 00:00:00' then 1
               when lastupdate > now() then 2
               else 3
          end),
         lastupdated asc;

如果您希望最后一组的排序降序，请执行：

order by (lastupdate > now()) desc,
         (case when lastupdate > now() then lastupdate end) asc,
         lastupdate desc

Answer 3

明确地对时间戳进行排序＆lt; NOW（）类似于您的排序方式＆gt; NOW（）

SELECT lastupdated FROM users ORDER BY lastupdated > NOW() DESC, lastupdated <= NOW() ASC;

MySQL查询ORDER BY DateTime问题

3 个答案: