Question

我正在Play中构建一个RESTful API，我的路线出现了一个奇怪的错误：

# Routes
# This file defines all application routes (Higher priority routes first)
# ~~~~

# Home page
GET     /                           controllers.Application.index()
GET     /api/getMessages            controllers.Application.getMessages()
POST    /api/createMessage          controllers.Application.createMessages(from:String, subject:String, message:String)

# Map static resources from the /public folder to the /assets URL path
GET     /assets/*file               controllers.Assets.at(path="/public", file)

/ api / createMessage给了我一些问题，当我发布一个完整的有效负载时，我收到错误：

For request 'POST /api/createMessage' [Missing parameter: from]

控制器：

public static Result createMessages(String from, String subject, String message){
    Message.create(from, subject, message);
    return ok(toJson("ok"));
}

请求正文：

Request Url: http://localhost:9000/api/createMessage
Request Method: POST
Status Code: 400
Params: {
    "from": "hello@test.com",
    "subject": "Hello",
    "message": "World"
}

有人可以帮帮我吗？

Answer 1

问题是，为了通过路径文件将参数传递给Java方法，这些参数应该是端点URL的一部分，这应该类似于POST /api/createMessage/:from/:subject/:message

对于你的情况，这不是一个好主意，你想要做的事情（从json对象传递参数）实际上是要走的路。所以你应该做的是用：

替换routes文件中的行

POST    /api/createMessage          controllers.Application.createMessages()

并使用createMessages方法读取JSON对象：

JsonNode data = request().body().asJson();
String from = data.get("from").textValue();
String subject = data.get("subject").textValue();
String message = data.get("message").textValue();

请确保您在请求中传递 Content-Type：application / json 标头，以便该游戏将请求正文理解为JSON对象。

Answer 2

问题是您在请求中通过邮寄方式发送数据

尝试

GET    /api/createMessage          controllers.Application.createMessages(from:String, subject:String, message:String)

和

Request Method: GET

此问题是因为您的请求在POST

中添加了参数

或者，如果你想在POST中

POST    /api/createMessage          controllers.Application.createMessages

控制器

public static Result createMessages{
String form =  //get it
String subject =  //get it
String message =  //get it
//not aware of java syntax too much but get here from form
Message.create(from, subject, message);
return ok(toJson("ok"));
}

当你标记 scala 时，意味着你熟悉scala，所以在scala控制器中

def createMessages = Action{
     implicit request =>
    val form = request.body.asFormUrlEncoded.get("form")(0)
    var subject = request.body.asFormUrlEncoded.get("subject")(0)
    var message = request.body.asFormUrlEncoded.get("message")(0)
    Message.create(from, subject, message)
    OK("ok")
}

Java Play POST [参数丢失]错误？

2 个答案: