Question

我正在两个自托管的Wordpress网站之间迁移大量用户，而我正在尝试找到一种方法将它们整合在一起，而无需重置密码。当前站点拥有每个人的密码，当然，所有密码都是很好的。目前，我可以看到导入这些用户的两种方法（wp_insert_user()和wp_create_user()）都要求密码为明文。有没有我缺少的东西，或者这是不是用现有方法完成的？

Answer 1

您有3个选项。运行自定义数据库查询，复制和修改wp_insert_user()，或运行wp_insert_user()两次。

复制并修改wp_insert_user()

以下是自定义wp_insert_user功能。我所做的只是删除了哈希值的行。

function wpse_custom_insert_user( $userdata ) {
    global $wpdb;

    if ( is_a( $userdata, 'stdClass' ) )
        $userdata = get_object_vars( $userdata );
    elseif ( is_a( $userdata, 'WP_User' ) )
        $userdata = $userdata->to_array();

    extract( $userdata, EXTR_SKIP );

    // Are we updating or creating?
    if ( !empty($ID) ) {
        $ID = (int) $ID;
        $update = true;
        $old_user_data = WP_User::get_data_by( 'id', $ID );
    } else {
        $update = false;
    }

    $user_login = sanitize_user($user_login, true);
    $user_login = apply_filters('pre_user_login', $user_login);

    //Remove any non-printable chars from the login string to see if we have ended up with an empty username
    $user_login = trim($user_login);

    if ( empty($user_login) )
        return new WP_Error('empty_user_login', __('Cannot create a user with an empty login name.') );

    if ( !$update && username_exists( $user_login ) )
        return new WP_Error( 'existing_user_login', __( 'Sorry, that username already exists!' ) );

    if ( empty($user_nicename) )
        $user_nicename = sanitize_title( $user_login );
    $user_nicename = apply_filters('pre_user_nicename', $user_nicename);

    if ( empty($user_url) )
        $user_url = '';
    $user_url = apply_filters('pre_user_url', $user_url);

    if ( empty($user_email) )
        $user_email = '';
    $user_email = apply_filters('pre_user_email', $user_email);

    if ( !$update && ! defined( 'WP_IMPORTING' ) && email_exists($user_email) )
        return new WP_Error( 'existing_user_email', __( 'Sorry, that email address is already used!' ) );

    if ( empty($nickname) )
        $nickname = $user_login;
    $nickname = apply_filters('pre_user_nickname', $nickname);

    if ( empty($first_name) )
        $first_name = '';
    $first_name = apply_filters('pre_user_first_name', $first_name);

    if ( empty($last_name) )
        $last_name = '';
    $last_name = apply_filters('pre_user_last_name', $last_name);

    if ( empty( $display_name ) ) {
        if ( $update )
            $display_name = $user_login;
        elseif ( $first_name && $last_name )
            /* translators: 1: first name, 2: last name */
            $display_name = sprintf( _x( '%1$s %2$s', 'Display name based on first name and last name' ), $first_name, $last_name );
        elseif ( $first_name )
            $display_name = $first_name;
        elseif ( $last_name )
            $display_name = $last_name;
        else
            $display_name = $user_login;
    }
    $display_name = apply_filters( 'pre_user_display_name', $display_name );

    if ( empty($description) )
        $description = '';
    $description = apply_filters('pre_user_description', $description);

    if ( empty($rich_editing) )
        $rich_editing = 'true';

    if ( empty($comment_shortcuts) )
        $comment_shortcuts = 'false';

    if ( empty($admin_color) )
        $admin_color = 'fresh';
    $admin_color = preg_replace('|[^a-z0-9 _.\-@]|i', '', $admin_color);

    if ( empty($use_ssl) )
        $use_ssl = 0;

    if ( empty($user_registered) )
        $user_registered = gmdate('Y-m-d H:i:s');

    if ( empty($show_admin_bar_front) )
        $show_admin_bar_front = 'true';

    $user_nicename_check = $wpdb->get_var( $wpdb->prepare("SELECT ID FROM $wpdb->users WHERE user_nicename = %s AND user_login != %s LIMIT 1" , $user_nicename, $user_login));

    if ( $user_nicename_check ) {
        $suffix = 2;
        while ($user_nicename_check) {
            $alt_user_nicename = $user_nicename . "-$suffix";
            $user_nicename_check = $wpdb->get_var( $wpdb->prepare("SELECT ID FROM $wpdb->users WHERE user_nicename = %s AND user_login != %s LIMIT 1" , $alt_user_nicename, $user_login));
            $suffix++;
        }
        $user_nicename = $alt_user_nicename;
    }

    $data = compact( 'user_pass', 'user_email', 'user_url', 'user_nicename', 'display_name', 'user_registered' );
    $data = wp_unslash( $data );

    if ( $update ) {
        $wpdb->update( $wpdb->users, $data, compact( 'ID' ) );
        $user_id = (int) $ID;
    } else {
        $wpdb->insert( $wpdb->users, $data + compact( 'user_login' ) );
        $user_id = (int) $wpdb->insert_id;
    }

    $user = new WP_User( $user_id );

    foreach ( _get_additional_user_keys( $user ) as $key ) {
        if ( isset( $$key ) )
            update_user_meta( $user_id, $key, $$key );
    }

    if ( isset($role) )
        $user->set_role($role);
    elseif ( !$update )
        $user->set_role(get_option('default_role'));

    wp_cache_delete($user_id, 'users');
    wp_cache_delete($user_login, 'userlogins');

    if ( $update )
        do_action('profile_update', $user_id, $old_user_data);
    else
        do_action('user_register', $user_id);

    return $user_id;
}

运行wp_insert_user两次

如果您运行wp_insert_user() user_pass，则应该是一个纯字符串。如果包含ID参数，则需要使用散列密码。

您可以使用随机密码运行wp_insert_user()来插入用户。这将返回一个ID。然后，您可以再次运行相同的功能，包括ID和散列密码。

正如我上面所指出的，这是低效的，而不是我建议的但是有可能。这是一个例子：

$hashed_pw = get_hashed_pw(); // Replace this with the correct hashed password.

$user_args = array(
    'ALL MY' => 'OTHER ARGS', // Enter all your other arguments for wp_insert_user().
    'user_pass' => 'random', // Set this to a random string.
);

$user_id = wp_insert_user( $user_args );

$update_user_args = array(
    'ID' => $user_id,
    'user_pass' => $hashed_pw,
);

wp_insert_user( $update_user_args );

这不是一个完整的解决方案。如果你要使用它，你会想要包括一些错误检查等等。你提出的另外两个解决方案之一会好得多。

使用预先散列的密码批量导入wordpress用户

1 个答案: