Question

我在Oracle 11g中搜索了有关数据透视的Stackoverflow，但找不到适合我情况的语法。

以下是我的查询（在Oracle 11g中运行）。

select
age,
gender,
sum(hours) as hours
from table1
group by age, gender

这是O / P结果

age gender   hours
25  Male     10
55  Female   5
45  Female   12

......这是我想要的O / P结果

Age  Male   Female
25   10     0
45    0     12
55    0     5

...这是我的查询

select *
from    
(
select
age,
gender,
sum(hours) as hours
from table1
)
pivot (
sum (hours) for gender in (
Male   as 'Male',
Female as 'Female')
)

......这是错误：

ORA-00931: missing identifier

有人可以请教育我吗？

Answer 1

你很亲密：

select age, nvl(male, 0) male, nvl(female, 0) female
from    
(
  select age,  gender,  sum(hours) as hours
  from table1
  group by age, gender
)
pivot
(
  sum(hours) for gender in ('Male' as male, 'Female' as female)
);

Answer 2

缺少标识符的原因＆＃39;错误是 - 预期的语法是

<Value> As <identifier>

所以，当你给予 - 男性为＆＃39;男性＆＃39; ，它＆＃39;之后找不到标识符。因此给出了这个错误。

即使你纠正了这个错误，下一个错误也会变成＆＃34;而不是单组组功能＆＃34;因为你选择年龄和性别以及总计函数总和（小时）而没有分组（我刚才提到这是一个技术点，你实际上并不需要这里的任何组）。

请参阅以下代码了解您的输出。

   SELECT age,nvl(male,0) AS male,nvl(female,0) AS frmale FROM 
    (SELECT * 
     FROM (
           SELECT age,gender,hours 
           FROM test_subha3) 
           pivot (sum(hours) FOR gender IN ('Male' AS Male,'Female' AS Female))
    )

转向Oracle 11g

2 个答案: