Question

我有一个包含以下列名的数据框：

 [1] "416362" "417510" "402634" "406503" "417510" "402634" "402634" "402634" "402634" "402634" "406801" "416631" "407508" "413513" "406801" "416362" "416631" "406603" "407508" "416631" "406603" "406531" "402634" "402634" "402634"
[26] "406503" "413513" "416631" "416631" "406531"

请注意，这些数字是混乱的，并且重复

我想重新组织列，以便它们遵循以下顺序：

[1] "402634" "406503" "406531" "406603" "406801" "407508" "413513" "416362" "416631" "417510"

所以我希望所有列号都在混乱的矩阵中有“402634”。然后，在矢量中，在混乱矩阵中具有“406503”的所有列号都说“x”。

然后，我想df[,x]重新组织我的数据框df。

谢谢！

Answer 1

在列名称上使用order命令：

currentNames = c("416362","417510","402634","406503","417510","402634","402634","402634","402634","402634",
                 "406801","416631","407508","413513","406801","416362","416631","406603","407508","416631",
                 "406603","406531","402634","402634","402634","406503","413513","416631","416631","406531")
df = data.frame(matrix(nrow=3,ncol=length(currentNames)))
colnames(df) = currentNames
df[1:nrow(df),1:ncol(df)] = runif(nrow(df)*ncol(df))
df = df[,order(colnames(df),decreasing=F)]

度假村列通过匹配两个不同的列表

1 个答案: