Question

我需要生成两个给定日期之间的天数列表。查询应该类似于

Select ... from ... where "date" is between date1 and date2

＆＃39; 2014-05-12＆＃39;和＆＃39; 2014-05-16＆＃39;应该是

Monday   | 2014-05-12
Tuesday  | 2014-05-13
Wednesday| 2014-05-14
Thursday | 2014-05-15
Friday   | 2014-05-16

开始和结束日期永远不会超过1个月，将来也是如此。我最好不要制作所有日期的表格或视图，但如果那是唯一的解决方案......

我找到了generate days from date range，但是给定的查询给出了错误，我根本不理解它，所以无法开始找到可能导致错误的内容。

感谢您的帮助

Answer 1

with days as (
   select date '2014-05-12' + (level - 1) as day
   from dual 
   connect by level <= date '2014-05-16' - date '2014-05-12' + 1
) 
select *
from days
order by day;

SQLFiddle：http://sqlfiddle.com/#!4/d41d8/29558

如果您需要定期使用此功能，最好为您创建一个功能：

create or replace type date_list as table of date
/

create or replace function generate_series(p_start_date date, p_end_date date)
  return date_list
  pipelined
is
  l_count integer;
begin
  l_count := trunc(p_end_date) - trunc(p_start_date);
  for i in 0..l_count loop
    pipe row (p_start_date + i);
  end loop;
end;
/

选择给定开始和结束日期之间的天数

1 个答案: