Question

我有以下代码用于将带有数据的文本文件加载到mysql表：

private final String filepath = "/mnt/sdcard/acc.txt";
private String acc;
public void insert()
{
    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    nameValuePairs.add(new BasicNameValuePair(filepath,acc));


    try
    {
    HttpClient httpclient = new DefaultHttpClient();
        HttpPost httppost = new HttpPost("http://testandroid.net/insert.php");
        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse response = httpclient.execute(httppost); 
        HttpEntity entity = response.getEntity();
        is = entity.getContent();
        Log.e("pass 1", "connection success ");
}
    catch(Exception e)
{
        Log.e("Fail 1", e.toString());
        Toast.makeText(getApplicationContext(), "Invalid IP Address",
        Toast.LENGTH_LONG).show();
}     

    try
    {
        BufferedReader reader = new BufferedReader
        (new InputStreamReader(is,"iso-8859-1"),8);
        StringBuilder sb = new StringBuilder();
        while ((line = reader.readLine()) != null)
    {
            sb.append(line + "\n");
        }
        is.close();
        result = sb.toString();
    Log.e("pass 2", "connection success ");
}
    catch(Exception e)
{
        Log.e("Fail 2", e.toString());
}     

try
{
        JSONObject json_data = new JSONObject(result);
        code=(json_data.getInt("code"));

        if(code==1)
        {
    Toast.makeText(getBaseContext(), "Inserted Successfully",
        Toast.LENGTH_SHORT).show();
        }
        else
        {
     Toast.makeText(getBaseContext(), "Sorry, Try Again",
        Toast.LENGTH_LONG).show();
        }
}
catch(Exception e)
{
        Log.e("Fail 3", e.toString());
}
}

这是我在服务器上的phpfile

<?php
    $host='xxx';
    $uname='yyy';
    $pwd='cfd';
    $db="dxw";

    $con = mysql_connect($host,$uname,$pwd) or die("connection failed");
    mysql_select_db($db,$con) or die("db selection failed");

    $id=$_REQUEST['id'];
    $name=$_REQUEST['name'];

    $flag['code']=0;

    if($r=mysql_query("LOAD DATA INFILE '$filepath' INTO TABLE xfr) ",$con))
{

        $flag['code']=1;
        echo"hi";
    }

    print(json_encode($flag));
    mysql_close($con);
?>

我一直收到无效的IP地址错误。我不知道自己做错了什么。请帮忙。我想在mysql服务器

中加载文本文件

Answer 1

如果它在此行生成异常：

httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));

这是因为名值对中的空内容或默认编码问题。您可以通过添加utf-8编码将其更改为以下行

httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs, "utf-8"));

Answer 2

这是一个大错误，或者我是如此虚伪......

您将文件名作为BasicNamevaluePair（http param）的键传递并且值为空字符串...

private String acc;
public void insert()
{
    ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
    nameValuePairs.add(new BasicNameValuePair(filepath,acc));

你必须阅读文件内容并传递它们

nameValuePairs.add(new BasicNameValuePair("data",getFileContent(filepath));

在php页面你读了2个没有从移动应用程序发送的参数

$id=$_REQUEST['id'];
$name=$_REQUEST['name'];

在php页面上，读取参数“data”，将其保存到文件 at server 并将其加载到db

$data=$_REQUEST['data'];
saveFile("myfile.txt", $data);
mysql_query("LOAD DATA INFILE myfile.txt INTO TABLE xfr") ",$con);

将数据从文本文件加载到android中的mysql服务器

2 个答案: