Question

今天我问候你，我的项目有一个程序问题，它使用光作为墙上伺服的输入。光将进入房间，阴影将下降，在没有光线的情况下，阴影将会消退。我想在arduino代码的void循环中创建两个条件，只适用一次，除非条件发生变化。通过这样说，我的意思是，我希望这个无效循环不断运行，我有两个条件。如果连续两次满足相同条件，（即传感器读数在800和10000之间，如5000，然后在6032），则不会运行任何操作。如果满足一个条件，然后另一个条件满足，那就没问题。这里是我的代码和任何有关我应该使用的参考命令或我的下一步行动的帮助将不胜感激。

// Reports the frequency from the TSL230, higher number means brighter
// Part: http://www.sparkfun.com/products/8940
// Article:  http://bildr.org/2011/08/tsl230r-arduino/ 

#include <Servo.h>
Servo myservo1;
int TSL230_Pin = 4; //TSL230 output
int TSL230_s0 = 3; //TSL230 sensitivity setting 1
int TSL230_s1 = 2; //TSL230 sensitivity setting 2

int TSL230_samples = 30; //higher = slower but more stable and accurate

void setup(){
  Serial.begin(9600);
  setupTSL230();
  pinMode(5,OUTPUT);
}


void loop(){

  float lightLevel = readTSL230(TSL230_samples);
  Serial.println(lightLevel);

if(lightLevel>800 && lightLevel<1000)
  {
    myservo1.attach(5);
    myservo1.writeMicroseconds(1300);delay(1000);
    myservo1.writeMicroseconds(1500);delay(5000000);  

}

else if(lightLevel<800)
{
  myservo1.attach(5);
  myservo1.writeMicroseconds(1700);delay(5000);
  myservo1.writeMicroseconds(1500);delay(5000000);
}
}

void setupTSL230(){
  pinMode(TSL230_s0, OUTPUT); 
  pinMode(TSL230_s1, OUTPUT); 

  //configure sensitivity - Can set to
  //S1 LOW  | S0 HIGH: low
  //S1 HIGH | S0 LOW:  med
  //S1 HIGH | S0 HIGH: high

  digitalWrite(TSL230_s1, LOW);
  digitalWrite(TSL230_s0, HIGH);
}



float readTSL230(int samples){
//sample light, return reading in frequency
//higher number means brighter

  float start = micros();  
  int readings = 0;

  while(readings < samples){
   pulseIn(TSL230_Pin, HIGH);
   readings ++;
  }

  float length = micros() - start;
  float freq = (1000000 / (length / samples)) * 10;

  return freq;
}

Answer 1

首先将此添加到您的设置中......

void setup(){
Serial.begin(9600);
setupTSL230();
pinMode(5,OUTPUT);
myservo1.attach(5);

}

然后创建一个新变量并将其添加到if语句

Boolean once; // declare this with your other int variables 
if(lightLevel > 800 && lightLevel < 1000 && once==True)
  {
    myservo1.writeMicroseconds(1300);delay(1000);
    myservo1.writeMicroseconds(1500);delay(1000);
    once = False;
  }
 else if(lightLevel<800 && once == False)
  {
    myservo1.writeMicroseconds(1700);delay(5000);
    myservo1.writeMicroseconds(1500);delay(1000);
    once = True;
   }

在某些条件下停止程序

1 个答案: