我目前正在尝试在SQL查询中转置一些数据但是我似乎找不到使用非透视的解决方案。我正在使用的数据示例是
SELECT * FROM (SELECT 'ACCOUNTS' AS Dept
, DATENAME(MONTH, GETDATE()) AS [Month]
, '3254' AS [1st Letter]
, '2544' AS [2nd Letter]
, '1254' AS [3rd Letter]
, '64' AS [4th Letter]
) AS t
我承认我并不完全理解PIVOT和UNPIVOT,但是如果它能在这个查询中起作用我似乎无法解决?期望的输出将是
Dept |ACCOUNTS
Month |May
1st Letter |3254
2nd Letter |2544
3rd Letter |1254
4th Letter |64
我在谷歌上看过很多解决方案,但并不是我想要的解决方案,对于我来说,这是不会做的事情。
答案 0 :(得分:1)
是。它只是有效。
declare @t table (Dept varchar(20), Month varchar(20), [1st letter]varchar(20),[2nd letter]varchar(20),[3rd letter]varchar(20),[4th letter]varchar(20))
insert @t
SELECT 'ACCOUNTS' AS Dept
, DATENAME(MONTH, GETDATE()) AS [Month]
, '3254' AS [1st Letter]
, '2544' AS [2nd Letter]
, '1254' AS [3rd Letter]
, '64' AS [4th Letter]
SELECT * FROM @t AS t
unpivot (item for value in (Dept, Month, [1st letter],[2nd letter],[3rd letter],[4th letter])) u
答案 1 :(得分:0)
SELECT
unpvt.[key],
unpvt.[value]
FROM
t
UNPIVOT
(
[key] FOR [value] IN ([Dept],[Month],[1st letter],[2nd letter],[3rd letter],[4th letter])
)
AS unpvt
UNPIVOT
有效地加入了一个包含两列的新表。如果是[key]
和[value]
。
[key]
是字段名称的字符串表示形式。
[value]
是存储在该字段中的值。
IN
列表允许您指定要转动的字段。
注意:这意味着您需要提前知道完整的字段名称列表;如果将它们添加到表中,它将不会动态调整以包含更多字段。此外,当您的字段具有不同的数据类型时要小心(尽管在您的示例中不是这种情况)。