帮助死锁分析

时间:2010-03-01 10:48:06

标签: static deadlock crt

当在使用参数DLL_THREAD_DETACH的DLLMain入口点调用的函数中发生本地静态变量的初始化时,我的应用程序中发生死锁。

以下是Windbg分析

这通常是由另一个持有加载程序锁的线程引起的。

以下是Locks Held。

CritSec ntdll!LdrpLoaderLock + 0 at 7c97e178

LockCount 3

RecursionCount 1

OwningThread 17e8

EntryCount d

ContentionCount d

***已锁定

CritSec MSVCR80!__ app_type + 94 at 781c3bc8

LockCount 1

RecursionCount 1

OwningThread 1100

EntryCount 1

ContentionCount 1 ***锁定

调用堆栈线程17e8

781c3bc8 78132bd9 0777fde4 ntdll!RtlEnterCriticalSection + 0x46

00000008 b87d2630 00000000 MSVCR80!_lock + 0x2e

0864ae10 08631d7f 0864ae10 EPComUtilities32!_onexit + 0x36

0864ae10 b87d2588 00000001 EPComUtilities32!atexit + 0x9

0777fea8 0864719f 08630000 EPComUtilities32!XCriticalSectionEx :: ThreadTerminated + 0x5f

08630000 00000003 00000000 EPComUtilities32!DllMain + 0x20

08630000 7c90118a 08630000 EPComUtilities32!__ DllMainCRTStartup + 0x7a

08630000 00000003 00000000 EPComUtilities32!_DllMainCRTStartup + 0x1d

调用堆栈线程1100

000000b0 00000000 00000000 ntdll!ZwWaitForSingleObject + 0xc

000000b0 ffffffff 00000000 kernel32!WaitForSingleObjectEx + 0xa8

000000b0 ffffffff 06ce64e0 kernel32!WaitForSingleObject + 0x12

000480ba 000f4240 00000000 CATSysMultiThreading!CATThreads :: Join + 0xf5

0012fcc8 00000004 00000000 JS0GROUP!CATLM :: StopHB + 0xf4

d138509f 00416694 00000001 JS0GROUP!CATLM :: Unmake + 0x6b

00000000 00000000 00000000 MSVCR80!_cinit + 0xd6

00000000 0012fd6c 081e68d9 MSVCR80!退出+ 0xd

00000000 06d404f0 0998fb90 JS0GROUP!CATExit + 0x1d

<00> 00000000 004ef366 0000000d DNBPLMProvider!DNBEPLMTransactionMgt :: OnApplicationExit + 0x229

<00> 00000000 0012fd9c 004eabfc JS0GROUP!CATCallExits + 0x2bc

<00> 00000000 0012ff7c 0040cefd JS0GROUP!CATErrorNormalEnd + 0x31 00000000 06ce71d0 06ce71d0 JS0GROUP!CATExit + 0xc

00000007 06cdb120 059b61d8 DLMMfgContextSolver!main + 0x146d

ffffffff ffffffff bffde000 DLMMfgContextSolver!__ tmainCRTStartup + 0x10f

请给出意见,了解可能导致死锁的原因。 注意:当我将静态变量设置为非静态时,问题会在论坛Deadlock occurs in Function Scoped Static variables (Thread Unsafe in VC++)

中发布的示例的上下文中消失

1 个答案:

答案 0 :(得分:0)

简而言之,造成僵局的原因是你something non-trivial in DllMain